Ask question

Ask question

All categories

3 years ago

6

a man buys and old bicycles for Rs 1850 and spend Rs 150 to repair it if he sells it at 25% profit find its selling price

1 answer:

AysviL [449]3 years ago

5 0

Answer:

Rs 2,500

Step-by-step explanation:

He has spent Rs1850 + Rs150 = Rs2000

if Rs2000 = 100%

X = 125%

By cross multiplication, we get;

100x = 2000 * 125

x = 250000/100

x = Rs 2,500

You might be interested in

Which ordered pairs lie on the graph of the exponential function f(x)=−3^(x−1) +2 Select each correct answer.

katrin [286]

<h3>Answer:</h3>

(1, 1), (4, -25)

<h3>Step-by-step explanation:</h3>

You can evaluate the function to see.

f(-1) = -3^(-1-1)+2 = -3^(-2)+2 = -1/9 +2 ≠ 2

f(1) = -3^(1-1) +2 = -1 +2 = 1

f(0) = -3^(0-1) +2 = -1/3 +2 ≠ 0

f(4) = -3^(4 -1) +2 = -27 +2 = -25

_____

Or, you can graph the points and the curve.

8 0

3 years ago

Compute the most rational way.

liraira [26]

1.=9900
2.=9.3
3.= x= 12.2155
Hope this helps

3 0

3 years ago

The liquid base of an ice cream has an initial temperature of 86°C before it is placed in a freezer with a constant temperature

Karolina [17]

The temperature of the ice cream 2 hours after it was placed in the freezer is 37.40 °C

From Newton's law of cooling, we have that

$T_{(t)}= T_{s}+(T_{0} - T_{s})e^{kt}$

Where

$(t) = \ time$

$T_{(t)} = \ the \ temperature \ of \ the \ body \ at \ time \ (t)$

$T_{s} = Surrounding \ temperature$

$T_{0} = Initial \ temperature \ of \ the \ body$

$k = constant$

From the question,

$T_{0} = 86 ^{o}C$

$T_{s} = -20 ^{o}C$

∴ $T_{0} - T_{s} = 86^{o}C - -20^{o}C = 86^{o}C +20^{o}C$

$T_{0} - T_{s} = 106^{o} C$

Therefore, the equation $T_{(t)}= T_{s}+(T_{0} - T_{s})e^{kt}$ becomes

$T_{(t)}=-20+106 e^{kt}$

Also, from the question

After 1 hour, the temperature of the ice-cream base has decreased to 58°C.

That is,

At time $t = 1 \ hour$ , $T_{(t)} = 58^{o}C$

Then, we can write that

$T_{(1)}=58 = -20+106 e^{k(1)}$

Then, we get

$58 = -20+106 e^{k(1)}$

Now, solve for $k$

First collect like terms

$58 +20 = 106 e^{k}$

$78 =106 e^{k}$

Then,

$e^{k} = \frac{78}{106}$

$e^{k} = 0.735849$

Now, take the natural log of both sides

$ln(e^{k}) =ln( 0.735849)$

$k = -0.30673$

This is the value of the constant $k$

Now, for the temperature of the ice cream 2 hours after it was placed in the freezer, that is, at $t = 2 \ hours$

From

$T_{(t)}=-20+106 e^{kt}$

Then

$T_{(2)}=-20+106 e^{(-0.30673 \times 2)}$

$T_{(2)}=-20+106 e^{-0.61346}$

$T_{(2)}=-20+106\times 0.5414741237$

$T_{(2)}=-20+57.396257$

$T_{(2)}=37.396257 \ ^{o}C$

$T_{(2)} \approxeq 37.40 \ ^{o}C$

Hence, the temperature of the ice cream 2 hours after it was placed in the freezer is 37.40 °C

Learn more here: brainly.com/question/11689670

6 0

2 years ago

Read 2 more answers

If the sum of six consecutive even integers is 306, what is the smallest of the six integers

Neko [114]

306/6 is 51 is you add one to one side and take away the other the six numbers become: 46, 48, 50, 52, 54, 56 as you added one to one side substituting the other you took away from, therefore the smallest would be 46.

4 0

3 years ago

!30 points! Which angle corresponds to angle N? (Photo attached)

aleksklad [387]

Answer:

The answer is D. "P". hope this helps you

4 0

3 years ago

Read 2 more answers