Answer:
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Answer:
a) t = 2 10⁻² s
, t = 2.4 10-1 s
Explanation:
In this exercise they indicate the delay in two signals
a) A signal travels on an electrical cable, between New York and London.
The wave formed in this wire for the signal. This wave travels at the speed of light, c = 3 108 m / s, so the delay is very small
t = d / c
t = 6000 10³/3 10⁸
t = 2 10⁻² s
b) The signal points to a satellite in geostationary orbit
distance traveled = √ (2 36000 10³)² + 6000²
distance = 72 10⁶ m
the waiting time is
t = d / c
t = 72 10⁶/3 10⁸
t = 2.4 10-1 s
we can see that the signal sent by the satellites has more delay because its distance is much greater
Answer:
There's a formula for finding the coefficient of friction i.e. μ = f÷N
hope it helps!
Acceleration = (change in velocity) / (time for the change) .
They may have had the same change in velocity, but if the changes
happened in different lengths of time, then their accelerations were
not the same.