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2 years ago

X -6,-3,0,3,6 y 0 1 2 3 4 which equation contains the coordinate parts given in the table

Mathematics

1 answer:

amid [387]2 years ago

7 0

The linear equation that contains the coordinate parts in the given table is: y = 1/3x + 2.

<h3>How to Find the Equation of a Linear Equation?</h3>

To find the linear equation that contains the coordinate parts in the table given, find the slope (m) and y-intercept (b), then substitute the values into y = mx + b.

Slope (m) using two coordinate parts, (0, 2) and (3, 3):

Slope (m) = change in y / change in x = (3 - 2)/(3 - 0)

Slope (m) = 1/3

y-intercept (b) = 2 [this is the value of y when x = 0)

Substitute the values into y = mx + b

y = 1/3x + 2.

Learn more about linear equation on:

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Answer:

The Width of the Rectangle = $10y^6$

$\text{Length of the Rectangle}=210y^8$

Step-by-step explanation:

The area of the rectangle $=70y^8 30y^6.$

We are told that the width of the rectangle is equal to the greatest common monomial factor of $70y^8 \: and\: 30y^6.$

Let us determine the greatest common monomial factor of $70y^8 \: and\: 30y^6.$

Express each term as a product to pick out the common factors:

$70y^8 =7X10Xy^6Xy^2\\30y^6=3X10Xy^6$

In the two terms, the common terms are 10 and $y^6$ . Therefore their greatest monomial factor = $10y^6$

The Width of the Rectangle = $10y^6$

Recall: Area of a Rectangle =Length X Width

$70y^8 30y^6=Length X 10y^6\\Length =70y^8 30y^6 \div 10y^6 \\=\dfrac{70X30Xy^8Xy^6}{10y^6} =210y^8\\\text{Length of the Rectangle}=210y^8$

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5. Let A = (x, y), B = {1,2). Find the Cartesian products of A and B: A x B? (Hint: the result will be a set of pairs (a, b) whe

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Answer: A x B = {(x,1), (x,2), (y,1), (y,2)}

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The Cartesian product of any two sets M and N is the set of all possible ordered pairs such that the elements of M are first values and the elements of N are the second values.

The Cartesian product of sets M and N is denoted by M × N.

For Example : M = {x,y} and N={a,b}

Then , M × N ={(x,a), (x,b), (y,a), (y,b)}

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Then , the Cartesian products of A and B will be :

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