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3 years ago

I need help on number 29

Mathematics

2 answers:

choli [55]3 years ago

7 0

x = All real numbers or 0.

First you should distribute both sides of the equation. This gives you 42x+42=42x+42.

Then, subtract 42 from both sides. This gives you 42x=42x.

Now, divide 42 on both sides. This gives you x=0 or all real numbers.

insens350 [35]3 years ago

4 0

When you get the same numbers on both sides of the equation. The answer is is all real numbers. Not 0

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Triangle XYZ has vertices X(0,3), Y(2,0) and Z(4,2). if yo reflect triangle XYZ across the line x=4, what will be the coordinate

Paha777 [63]

As X' is the reflected point of X(0,3) , so the x co ordinate of X' = 0+8 =8 and here y co ordinate remains same.

So, X'= (8,3)

Like that way, Y' is the reflected point of Y(2,0) and Z' is the reflected point of Z(4,2)

As the point Z is lying on the line x=4 and the reflection is also across that line, so both Z and Z' represent same point.

Y'= (2+4, 0) = (6, 0)

Z' = (4, 2)

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3 years ago

Esessment

Klio2033 [76]

The area of the given composite figure is 34 square feet

<h3>Area of rectangle</h3>

Area of the rectangle = length * width

<h3>Get the area of the given composite figure</h3>

For the composite figure shown:

Area = (8*3) + (2 * 5)

Area = 24 + 10

Area = 34 square feet

Hence the area of the given composite figure is 34 square feet

Learn more on area of rectangle here: brainly.com/question/25292087

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2 years ago

What is the length of the curve with parametric equations x = t - cos(t), y = 1 - sin(t) from t = 0 to t = π? (5 points)

zzz [600]

Answer:

B) 4√2

General Formulas and Concepts:

<u>Calculus</u>

Differentiation

Derivatives
Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Parametric Differentiation

Integration

Integrals
Definite Integrals
Integration Constant C

Arc Length Formula [Parametric]: $\displaystyle AL = \int\limits^b_a {\sqrt{[x'(t)]^2 + [y(t)]^2}} \, dx$

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

$\displaystyle \left \{ {{x = t - cos(t)} \atop {y = 1 - sin(t)}} \right.$

Interval [0, π]

<u>Step 2: Find Arc Length</u>

[Parametrics] Differentiate [Basic Power Rule, Trig Differentiation]: $\displaystyle \left \{ {{x' = 1 + sin(t)} \atop {y' = -cos(t)}} \right.$
Substitute in variables [Arc Length Formula - Parametric]: $\displaystyle AL = \int\limits^{\pi}_0 {\sqrt{[1 + sin(t)]^2 + [-cos(t)]^2}} \, dx$
[Integrand] Simplify: $\displaystyle AL = \int\limits^{\pi}_0 {\sqrt{2[sin(x) + 1]} \, dx$
[Integral] Evaluate: $\displaystyle AL = \int\limits^{\pi}_0 {\sqrt{2[sin(x) + 1]} \, dx = 4\sqrt{2}$