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1 year ago

Find the image of G when A IMG is rotated 180 around the origin.

Mathematics

1 answer:

Afina-wow [57]1 year ago

7 0

.2,\[; kwsko. weqaszzeqzsew cre [~,/4_

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A farmer wants to use 200 feet of fencing for a chicken pen. He wants the width of the pen to be 20 feet. What is the length of

Aneli [31]

The length should be 80 feet.

This is because the width is 20, since there are two sides for the width in a pen, we have to add 20+20. This would equal 40. Then we need to subtract 40 from 200. 200-40 would be 160. Then since there are two sides for the length, we need to split that in half. 160÷2 would be 80. To double check, you can do 80+80 and that would still be 160. So the length of one side would be 80. But of course, this whole thing would only be right if the pen has four sides(but since i have seen many chicken pens, there were all rectangular). I hope this helped! :)

7 0

2 years ago

Multiply these binomials using foil method (b+3)(b-9)

sleet_krkn [62]

FOIL stands for first, outer, inner, and last.
So, you multiply the first terms together, the outer terms together, the inner terms together, and then the last terms together.
(b+3)(b-9)
b^2-9b+3b-27 Then simplify
b^2-6b-27

3 0

3 years ago

What is 14g-98+3g when g is 7

pochemuha

So there are two potential ways you could do this. First just multiple the g=7 into the equation and then add. Or another possibility is to first add the 14g and 3g to get the 17g and then multiply it by the g value and subtract 98. So if we combine the g's and then multiply it by 7, the 17g becomes $17*7=119$ . So now subtract 98 from 119, $119-98=21$ . So the overall answer to the expression is 21 when g equals 7.

6 0

3 years ago

Read 2 more answers

Solve for x please describe the steps 50 points

LuckyWell [14K]

Answer:

x = 6

explanation:

USE: $\boxed{\frac{side-length }{base -length} = \frac{side-length}{base -length} }$

solve:

$\frac{21}{15} = \frac{7}{x-1}$

$21(x-1) = 7(15)$

$21x-21 = 105$

$21x = 105+21$

$21x = 126$

$x = \frac{126}{21}$

$x = 6$

8 0

2 years ago

A quality-conscious disk manufacturer wishes to know the fraction of disks his company makes which are defective. Step 2 of 2 :

Diano4ka-milaya [45]

Answer: (0.120,0.160)

Step-by-step explanation:

Given : Sample size : $n=815$

Number of disks were not defective =701

Then , the number of disks which are defective = $815-701=114$

Now, the proportion of disks which are defective : $p=\dfrac{114}{815}\approx0.14$

Significance level : $\alpha: 1-0.9=0.1$

Critical value : $z_{\alpha/2}=1.645$

The confidence interval for population proportion is given by :-

$p\pm\ z_{\alpha/2}\sqrt{\dfrac{p(1-p)}{n}}\\\\=0.14\pm(1.645)\sqrt{\dfrac{(0.14)(1-0.14)}{815}}\\\\\approx0.14\pm0.020=(0.14-0.020,0.14+0.020)=(0.120,0.160)$

Hence, the 90% confidence interval for the population proportion of disks which are defective = (0.120,0.160)

7 0

2 years ago