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AnnZ [28]
3 years ago
6

Eliminate the parameter. x = 1/2t, y = 3t^3 - 1

Mathematics
1 answer:
Elis [28]3 years ago
4 0
X = t/2. t = 2x
y = 3t^3 - 1
y = 3(2x)^3 -1

y = 24x^3 -1
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The heights of baby giraffe are normally distributed with a mean of 63.6 inches and a standard deviation of 2.5 inches. If 100 b
ANEK [815]

Answer:

P(\bar X

And we can solve this using the following z score formula:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And if we use this formula we got:

z = \frac{63-63.6}{\frac{2.5}{\sqrt{100}}}= -2.4

So we can find this probability equivalently like this:

P( Z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:

X \sim N(63.6,2.5)  

Where \mu=63.6 and \sigma=2.5

We select n =100. Since the distribution for X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

We want this probability:

P(\bar X

And we can solve this using the following z score formula:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And if we use this formula we got:

z = \frac{63-63.6}{\frac{2.5}{\sqrt{100}}}= -2.4

So we can find this probability equivalently like this:

P( Z

4 0
3 years ago
This is review, please help it’s due tomorrow!
Svet_ta [14]
I dont see anything
3 0
2 years ago
In roulette, you may bet whether the number that comes up is odd (or even). (Remember that 0 and 00 do not count as either odd o
EastWind [94]

Answer: - 0.027

Step-by-step explanation:

Win = any even number between (0 - 36)

Therefore,

Lose = any odd number between 0 —36 including 0

Assume Bet amount = $1

Expected value is calculate by summing all possible outcomes by their respective probabilities.

Expected value = [(p(winning) × net win value) + (p(losing +net loss value]

P(winning) = p(even) = 18/37

P(losing) = p(odd) +p(0) = 19/37

Net win value = $2

Net loss value = $-1

Expected value = [(18/37) × ($1) + (19/37) × (-$1)]

Expected value = 0.48648648 - 0.51351351

Expected value = - 0.027

7 0
3 years ago
At a local pool club they advocate having 1 lifeguard for every 50 people.
kifflom [539]
C

Hope I helped! :-)

~Sequoyah! :-)

5 0
3 years ago
What is the mean deviation of the following numbers 2 4 6 8 10 12​
olga nikolaevna [1]

Step-by-step explanation:

mean is always equal to additon of total no.s by total no.s

2 + 4 + 6 + 8 + 10 + 12

=42

total no.s = 6 no.s

42/6

=7

therefore 7 is the answer which is the mean deviation of the following no.s .

3 0
3 years ago
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