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adoni [48]
2 years ago
6

Which of the following is a Recursive Formula for an Arithmetic Sequence?

Mathematics
1 answer:
In-s [12.5K]2 years ago
3 0

The Recursive formula for an Arithmetic Sequence is a1 = -3, an = an-1 + 6.

<h3>What is Arithmetic sequence ?</h3>

An arithmetic sequence is a sequence where each term increases by adding/subtracting some constant k.

Given:

an = -3 + 6(n – 1)

a1= -3

a2= 3

a3 = 9

Here the common difference is 6 and first term is -3

Hence, the recursive formula is a1 = -3, an = an-1 + 6.

Learn more about this concept here:

brainly.com/question/12942847

#SPJ1

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Write and solve an equation to find the value of x and a missing angle in the triangle below.
Oksi-84 [34.3K]

Answer:

angle UTS +TSU =TUV

THEREFORE, 81 + 12X =24X+9

THEREFORE, 81 - 9 = 24X - 12X

THEREFORE, 72 = 12X

THEREFORE, 72/12 =X

THEREFORE, x = 6

THEREFORE, ANGLE TSU = 12 * X

= 12 *6

= 72

YOUR ANSWER IS

X=6

TSU=72

THANK YOU......

6 0
3 years ago
The graph of the equation x^2+6x+y^2-16y=-9 is a circle. Choose True or False for each statement
BigorU [14]

Answer:

see the explanation

Step-by-step explanation:

we have

x^2+6x+y^2-16y=-9

<u><em>Convert the equation of the circle in center radius form</em></u>

Group terms that contain the same variable

(x^2+6x)+(y^2-16y)=-9

Complete the square twice. Remember to balance the equation by adding the same constants to each side

(x^2+6x+9)+(y^2-16y+64)=-9+9+64

(x^2+6x+9)+(y^2-16y+64)=64

Rewrite as perfect squares

(x+3)^2+(y-8)^2=8^2

The center of the circle is (-3,8)

The radius of the circle is 8 units

<u><em>Verify each statement</em></u>

A. The center of the circle is (3,-8).

False

The center of the circle is (-3,8)

B. The circle is tangent to the x-axis

True

The circle is tangent to x=5 and x=-11 and is tangent to y=0 and y=16

Remember that y=0 is the x-axis

C. The circle has a radius of 64

False

The radius of the circle is 8 units

7 0
3 years ago
Simplify 3×+1(2×-1)2-1(6×)​
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●✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎❀✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎●

Hi my lil bunny!

❧⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯☙

Answer =   \boxed {x - 2}

3x +1(2x-1)2-1(6x)

= \boxed {3x + 1 . ( 2x - 1 ) . 2 - 1 (6x) = x - 2}

Steps :

3x + 1 . (2x - 1) . 2 - 1 . (6x)

Remove the parentheses : (a) = a

= 3x + 1 * (2x- 1) * 2 - 1 * 6x

Multiply the numbers : 1 * 2 = 2

= 3x + 2 ( 2x - 1 ) * 6x

Multiply the numbers : 1 * 6 = 6

= 3x + 2 ( 2x - 1 ) -6x

Expand: 2 (2x - 1) :   4x - 2

2 ( 2x - 1 )

Apply the distributive law : a (b - c) = ab - ac

a = 2, b = 2x, c = 1 \\= 2 * 2x - 2 * 1

Simplify 2 * 2x - 2 * 1 : 4x - 2

= = 4x - 2

= 3x + 4x - 2 - 6x

Simplify 3x + 4x - 2 - 6x : x - 2

= x - 2

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the answer is 106.30

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3 years ago
Simplify (4 - x²)/2x - x² where x≠0 and x≠2​
GuDViN [60]

Answer

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Step-by-step explanation:

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3 years ago
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