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cluponka [151]
3 years ago
5

Jerry thought four DVDs $425.20. What was the unit rate?

Mathematics
1 answer:
Romashka-Z-Leto [24]3 years ago
8 0

the answer is 106.30

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Please help stuck on probelem
Maurinko [17]
<h3>Answer:  36 square units</h3>

=========================================================

Explanation:

Draw a horizontal line to cut the figure into a rectangle on top and a triangle down below.

The rectangle has length and width of 6 and 4 (horizontal and vertical components respectively). The area of this rectangle is 6*4 = 24 square units.

The triangle has a base of 6 and a height of 4. The base and height of any triangle are always perpendicular.

The area of the triangle is base*height/2 = 6*4/2 = 24/2 = 12 square units. If you were to cut out half of the triangle and rearrange things, you'll find that a rectangle can be formed. This rectangle is half in area that of the first rectangle we found. This is why we divide by 2 when finding the area of the triangle.

Once you know the two sub-areas, we add them up to get the overall area: 24+12 = 36 square units.

5 0
3 years ago
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Which of these equations would be parallel to a line a slope of -7?
Shtirlitz [24]
Where’s the picture at
5 0
3 years ago
Let f(x)=4x2+5. The function g(x) is f(x) translated up 4 units. Enter the equation of g(x) in the box.
Zepler [3.9K]
Al you have to do is add 4 to the equation
This gives you g(x)=4x^2+9 which is your answer

6 0
4 years ago
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Jay has 195 baseball cards, Jen has 46 more than Jay, how many more cards does Jen have than Jay? (I will give brainliest)
bogdanovich [222]
Jen has 46 more than Jay, “Jen has 46 more than Jay.” You answered your own question.
6 0
2 years ago
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Complex numbers zj and zz are given by zj = 3- j2, zz = - 4 + j3. (a) express zj and zz in polar form. (b) find lz1l by first ap
inna [77]

Solution:

Given: zj = 3- j2, zz = - 4 + j3

Part a:

zj = 3- j2 = 3.6e^{-j33.7^{\circ}}

zz = - 4 + j3 = 5e^{j143.1^{\circ}}

Part b:

|zj| = |3− j2| =  √3² +(−2)² = √13 = 3.60

|z1| =  √(3− j2)(3+ j2) = √ 13 = 3.60.

Part c:

With the help of part a:

z1z2 = 3.6e^{-j33.7^{\circ}}.5e^{j143.1^{\circ}}

6 0
3 years ago
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