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lutik1710 [3]
2 years ago
7

Suppose $n$ is a positive integer such that $6n$ has exactly 9 positive divisors. How many prime numbers are divisors of $6n$

Mathematics
1 answer:
zvonat [6]2 years ago
6 0

The number of prime divisors of "6n" is 2 numbers 2 and 3

Given

"n"  = 6    

thus 6n  = 6(6) = 36

The positive divisors are   1, 2, 3, 4, 6, 9, 12, 18 and 36

So, the number of prime divisors of "6n" is 2 numbers 2 and 3.

The prime factors of a positive integer are the top numbers that divide that integer exactly. The technique of finding those numbers is known as integer factorization or prime factorization.

The fundamental theorem of mathematics says that every positive integer has a completely unique prime factorization.

Learn more about prime factorization here: brainly.com/question/1081523

#SPJ4

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Sliva [168]

Answer:

y-18=-2(x+2)^2

Step-by-step explanation:

Equation of the Quadratic Function

The vertex form of the quadratic function has the following equation:

y-k=a(x-h)^2

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It's been given the vertex of the parabola as (-2,18):

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a = -18 / 9

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Thus, the equation of the quadratic function is:

\mathbf{y-18=-2(x+2)^2}

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Step-by-step explanation:

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Write a ratio, in the simplest form and a percent for the shaded area (there's a 5x4 box and 6 cubes are shaded)
Alexxandr [17]

Answer:

\%Percent = 30 \%

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Given

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<em>30% were shaded</em>

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