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1 year ago

Suppose $n$ is a positive integer such that $6n$ has exactly 9 positive divisors. How many prime numbers are divisors of $6n$

Mathematics

1 answer:

zvonat [6]1 year ago

6 0

The number of prime divisors of "6n" is 2 numbers 2 and 3

Given

"n" = 6

thus 6n = 6(6) = 36

The positive divisors are 1, 2, 3, 4, 6, 9, 12, 18 and 36

So, the number of prime divisors of "6n" is 2 numbers 2 and 3.

The prime factors of a positive integer are the top numbers that divide that integer exactly. The technique of finding those numbers is known as integer factorization or prime factorization.

The fundamental theorem of mathematics says that every positive integer has a completely unique prime factorization.

Learn more about prime factorization here: brainly.com/question/1081523

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3 years ago

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What is the quotient? Negative StartFraction 3 over 8 EndFraction divided by negative one-fourth

anyanavicka [17]

Answer:

$\dfrac{3}{2}$

Step-by-step explanation:

We are given 2 fractions.

1st fraction is Negative StartFraction 3 over 8

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$-\dfrac{3}{8}$

2nd fraction is negative one-fourth

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Definition of quotient is given as:

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$-\dfrac{3}{8} \div -\dfrac{1}{4} \text{ is to be calculated.}$

$\div$ is converted to $\times$ and the 2nd fraction is reversed i.e.

if the fraction is $\frac{p}{q}$ it becomes $\frac{q}{p}$ and the sign $\div$ is changed to $\times$ .

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2 years ago

Which functions have an axis of symmetry of x = -2? Check all that apply. A. f(x) = x^2 + 4x + 3 B. f(x) = x^2 - 4x - 5 C. f(x)

Snowcat [4.5K]

Answer:

A. f(x) = x^2 + 4x + 3

D. f(x) = -2x^2 - 8x + 1

Step-by-step explanation:

The axis of symmetry is found by h = -b/2a where ax^2 +bx +c

A. f(x) = x^2 + 4x + 3

h = -4/2*1 = -2 x=-2

B. f(x) = x^2 - 4x - 5

h = - -4/2*1 = 4/2 =2 x=2 not -2

C. f(x) = x^2 + 6x + 2

h = -6/2*1 = -3/2 = x=-3/2 not -2

D. f(x) = -2x^2 - 8x + 1

h = - -8/2*-2 = 8/-4 =-2 x=-2

E. f(x) = -2x^2 + 8x - 2

h = - 8/2*-2 = -8/-4 =2 x=2 not -2

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