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Gre4nikov [31]
2 years ago
6

Write a ratio, in the simplest form and a percent for the shaded area (there's a 5x4 box and 6 cubes are shaded)

Mathematics
1 answer:
Alexxandr [17]2 years ago
5 0

Answer:

\%Percent = 30 \%

Step-by-step explanation:

Given

Shaded = 6\ cubes

Box = 5\ x\ 4

Required

Determine the percentage of the shaded cubes

First, we calculate the number of boxes:

Box = 5\ x\ 4

Express as multiplication

Box = 5\ *\ 4

Box = 20

This implies that there are 20 cubes in the box.

The percentage of the shaded cubes is:

\%Percent = \frac{Shaded}{Box} * 100\%

\%Percent = \frac{6}{20} * 100\%

\%Percent = \frac{6* 100}{20} \%

\%Percent = \frac{600}{20} \%

\%Percent = 30 \%

<em>30% were shaded</em>

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Find the distance between the points (-10, -9) and (-7, -1).
QveST [7]

Answer:

Distance: 8.5440037453175

Step-by-step explanation:

Distance: 8.5440037453175

Steps:

Distance (d) = √(-7 - -10)2 + (-1 - -9)2

= √(3)2 + (8)2

= √73

= 8.5440037453175

Slope and Angle:

ΔX = -7 – -10 = 3

ΔY = -1 – -9 = 8

Slope (m) =  

ΔY

ΔX

=  

8

3

= 2.6666666666667

θ =  

arctan( ΔY )

ΔX

= 69.443954780417°

Equation of the line:

y = 2.6666666666667x + 17.666666666667

or

y =  

8 x

3

+  53

3

When x=0, y = 17.666666666667

When y=0, x = -6.625

3 0
3 years ago
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Find the area. The figure is not drawn to scale. Please show work
Irina-Kira [14]

Answer:

13.8 square feet

Step-by-step explanation:

To find the area of a triangle you use the formula a = 1/2 bh

a = 1/2 (6.9) (4) = 13.8

(simplier to understand) a = 1/2 (6.9) (4) = 27.6 divided by 1/2 = 13.8

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Need help with this
harina [27]

Answer:

Qu. 8 = A (50) = 25w  as 125w x 125l = Area ; this because perimeter 500ft would always be a 3:5 ratio to the larger area. Therefore perimeter is 125+125 +125 +125 and = 500ft. However we can prove if 125 is any length or width then A(50)= 1/5 = 25   Qu 9)= I think last 2 are a function. Qu 10) Answer B is correct.

Step-by-step explanation:

5 0
3 years ago
In ΔLMN, \overline{LN}
Karolina [17]

Answer:

\bold{\angle NLM = 10^\circ}

Step-by-step explanation:

Given a ΔLMN.

Line LN is extended to point O.

such that:

\text{m}\angle MNO = (5x-13)^{\circ}

\text{m}\angle NLM = (x-4)^{\circ} and

\text{m}\angle LMN = (2x+19)^{\circ}

To find:

\text{m}\angle NLM=?

Solution:

Kindly refer to the attached image for the given triangle and dimensions of angles.

Let us recall the external angle property of a triangle:

The external angle of a triangle is equal to the sum of two opposite internal angles.

i.e.

\angle MNO = \angle NLM + \angle LMN\\\Rightarrow 5x-13 = x-4+2x+19\\\Rightarrow 5x-13 = 3x+15\\\Rightarrow 5x-3x = 13+15\\\Rightarrow 2x=28\\\Rightarrow x =14

Putting the value of x in \angle NLM.

\angle NLM=14-4 \\\Rightarrow \bold{\angle NLM = 10^\circ}

5 0
3 years ago
There is a circle with a center of 0,0 on a coordinate plane. There is one point on the circle's circumference in which the x:y
abruzzese [7]

Answer:

Step-by-step explanation:

Suppose the radius is 1. The parametric equations for the circle are

x = cosθ

y = sinθ

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sinθ = 1/√10

The solutions are (3/√10, 1/√10) and (-3/√10, -1/√10).

6 0
3 years ago
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