Ask question

Ask question

All categories

3 years ago

11

The miniature golf scores for 7 friends are 23, 30, 39, 32, 35, 14, and 23. What is the mean golf score for this group of friend

s?

1 answer:

Vika [28.1K]3 years ago

4 0

(23+30+39+32+35+14+23)/7
=28 which is the mean score for this group of friends.

You might be interested in

Y=74(1.01)^8 is it increasing or decreasing

Dvinal [7]

Answer:

Increasing

Step-by-step explanation:

The computation is given below:

Given that

y = 74 × (1.01)^8

= 74 × 1.082856706

= 80.1314

As it can be seen that the initial amount is 74 but after solving the given equation the value is increased as it shows 80.1314

Therefore it is increasing

5 0

3 years ago

Find the dimensions of the open rectangular box of maximum volume that can be made from a sheet of cardboard 21 in. by 12 in. by

a_sh-v [17]

Answer:

Dimension of the box is $16.1\times 7.1\times 2.45$

The volume of the box is 280.05 in³.

Step-by-step explanation:

Given : The open rectangular box of maximum volume that can be made from a sheet of cardboard 21 in. by 12 in. by cutting congruent squares from the corners and folding up the sides.

To find : The dimensions and the volume of the box?

Solution :

Let h be the height of the box which is the side length of a corner square.

According to question,

A sheet of cardboard 21 in. by 12 in. by cutting congruent squares from the corners and folding up the sides.

The length of the box is $L=21-2h$

The width of the box is $W=12-2h$

The volume of the box is $V=L\times W\times H$

$V=(21-2h)\times (12-2h)\times h$

$V=(21-2h)\times (12h-2h^2)$

$V=252h-42h^2-24h^2+4h^3$

$V=4h^3-66h^2+252h$

To maximize the volume we find derivative of volume and put it to zero.

$V'=12h^2-132h+252$

$0=12h^2-132h+252$

Solving by quadratic formula,

$h=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$h=\frac{-(-132)\pm\sqrt{132^2-4(12)(252)}}{2(12)}$

$h=\frac{132\pm72.99}{24}$

$h=2.45,8.54$

Now, substitute the value of h in the volume,

$V=4h^3-66h^2+252h$

When, h=2.45

$V=4(2.45)^3-66(2.45)^2+252(2.45)$

$V\approx 280.05$

When, h=8.54

$V=4(8.54)^3-66(8.54)^2+252(8.54)$

$V\approx -170.06$

Rejecting the negative volume as it is not possible.

Therefore, The volume of the box is 280.05 in³.

The dimension of the box is

The height of the box is h=2.45

The length of the box is $L=21-2(2.45)=16.1$

The width of the box is $W=12-2(2.45)=7.1$

So, Dimension of the box is $16.1\times 7.1\times 2.45$

6 0

3 years ago

A side of an equilateral triangle is 2/8 cm long. Draw a picture that shows the triangle

lianna [129]

Here you go. I hope this will help

7 0

4 years ago

Give me the answer pll

STatiana [176]

Product means multiply, a number means any variable so 6x is the answer

3 0

3 years ago

I need help on ratio of x-coordinates and ratio of y-coordinates

ad-work [718]

Answer:

Ratio of x-coordinates:

$\frac{-1}{-2}=\frac{1}{2}$

$\frac{2}{4}=\frac{1}{2}$

$\frac{2}{4}=\frac{1}{2}$

$\frac{-2}{-4}=\frac{1}{2}$

Ration of y-coordinates:

$\frac{2.5}{5}=\frac{1}{2}$

$\frac{1}{2}=\frac{1}{2}$

$\frac{-2}{-4}=\frac{1}{2}$

$\frac{-2}{-4}=\frac{1}{2}$

Step-by-step explanation:

The table is asking for the ratio of x-coordinates for each point (A, B, C and D) for both the image and pre-image. The ratio is the image 'x' or 'y' value ÷ the pre-image 'x' or 'y' value. Each ratio should be expressed in simplest form and should show the same pattern of dilation, or same scale factor. In this case, the second figure is 1/2 the size of the original figure.

5 0

3 years ago