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3 years ago

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The miniature golf scores for 7 friends are 23, 30, 39, 32, 35, 14, and 23. What is the mean golf score for this group of friend

s?

1 answer:

Vika [28.1K]3 years ago

4 0

(23+30+39+32+35+14+23)/7
=28 which is the mean score for this group of friends.

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An airplane is 32,000 feet above the ground begins descending at a rate 2,500

grandymaker [24]

Answer:

32000-2500x, let x equal number of minutes.

Step-by-step explanation:

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3 years ago

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The function in Exercise represents the rate of flow of money in dollars per year. Assume a 10-year period at 8% compounded cont

Kryger [21]

Answer:

a) $P= $56,972.5$

b) $A=$1,26,792.3$

Step-by-step explanation:

Given Data:

Interest rate= $r= 0.08$ per year

No. of years= $t=10$

Rate of continuous money flow is given by the function

$f(t)=2000$

a) to find the present value of money

$P=\int\limits^n_0 {f(t)e^{-rt} } \, dt$

Put f(t)=2000 and n=10 years and r=0.08

$P=\int\limits^n_0 {2000e^{-0.08t} } \, dt$

Now integrate

$P= {2000(\frac{e^{-0.08t}}{-0.08} )$

$P= -\frac{2000}{0.08} (e^{-0.08*10}-e^{-0.08*0})$

$P= -\frac{2000}{0.08} (e^{-0.8}-e^{0})$

$P= -\frac{2000}{0.08} (0.4493-2.7282)$

$P= -\frac{2000}{0.08} (-2.2789)$

$P= -25000(-2.2789)$

$P= $56972.5$

(b) to find the accumulated amount of money at t=10

$A=P(e^{rt} )$

Where P is the present worth already calculated in part a

$A=56972.5(e^{0.08*10} )$

$A=56972.5(e^{0.8} )$

$A=56972.5(2.2255 )$

$A=$1,26,792.3$

5 0

3 years ago

Is anybody else here to help me ??

Akimi4 [234]

Answer:

$\cot(x)+\cot(\frac{\pi}{2}-x)$

$\cot(x)+\tan(x)$

$\frac{\cos(x)}{\sin(x)}+\frac{\sin(x)}{\cos(x)}$

$\frac{1}{\sin(x)}(\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)})$

$\csc(x)(\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)})$

$\csc(x)[\frac{\cos(x)\cos(x)}{\cos(x)}+\sin(x)\frac{sin(x)}{\cos(x)}]$

$\csc(x)[\frac{\cos(x)\cos(x)+\sin(x)\sin(x)}{\cos(x)}]$

$\csc(x)[\frac{\cos^2(x)+\sin^2(x)}{\cos(x)}]$

$\csc(x)[\frac{1}{\cos(x)}]$

$\csc(x)[\sec(x)]$

$\csc(x)[\csc(\frac{\pi}{2}-x)]$

$\csc(x)\csc(\frac{\pi}{2}-x)$

Step-by-step explanation:

I'm going to use $x$ instead of $\theta$ because it is less characters for me to type.

I'm going to start with the left hand side and see if I can turn it into the right hand side.

$\cot(x)+\cot(\frac{\pi}{2}-x)$

I'm going to use a cofunction identity for the 2nd term.

This is the identity: $\tan(x)=\cot(\frac{\pi}{2}-x)$ I'm going to use there.

$\cot(x)+\tan(x)$

I'm going to rewrite this in terms of $\sin(x)$ and $\cos(x)$ because I prefer to work in those terms. My objective here is to some how write this sum as a product.

I'm going to first use these quotient identities: $\frac{\cos(x)}{\sin(x)}=\cot(x)$ and $\frac{\sin(x)}{\cos(x)}=\tan(x)$

So we have:

$\frac{\cos(x)}{\sin(x)}+\frac{\sin(x)}{\cos(x)}$

I'm going to factor out $\frac{1}{\sin(x)}$ because if I do that I will have the $\csc(x)$ factor I see on the right by the reciprocal identity:

$\csc(x)=\frac{1}{\sin(x)}$

$\frac{1}{\sin(x)}(\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)})$

$\csc(x)(\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)})$

Now I need to somehow show right right factor of this is equal to the right factor of the right hand side.

That is, I need to show $\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)}$ is equal to $\csc(\frac{\pi}{2}-x)$ .

So since I want one term I'm going to write as a single fraction first:

$\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)}$

Find a common denominator which is $\cos(x)$ :

$\frac{\cos(x)\cos(x)}{\cos(x)}+\sin(x)\frac{sin(x)}{\cos(x)}$

$\frac{\cos(x)\cos(x)+\sin(x)\sin(x)}{\cos(x)}$

$\frac{\cos^2(x)+\sin^2(x)}{\cos(x)}$

By the Pythagorean Identity $\cos^2(x)+\sin^2(x)=1$ I can rewrite the top as 1:

$\frac{1}{\cos(x)}$

By the quotient identity $\sec(x)=\frac{1}{\cos(x)}$ , I can rewrite this as:

$\sec(x)$

By the cofunction identity $\sec(x)=\csc(x)=(\frac{\pi}{2}-x)$ , we have the second factor of the right hand side:

$\csc(\frac{\pi}{2}-x)$

Let's just do it all together without all the words now:

$\cot(x)+\cot(\frac{\pi}{2}-x)$

$\cot(x)+\tan(x)$

$\frac{\cos(x)}{\sin(x)}+\frac{\sin(x)}{\cos(x)}$

$\frac{1}{\sin(x)}(\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)})$

$\csc(x)(\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)})$

$\csc(x)[\frac{\cos(x)\cos(x)}{\cos(x)}+\sin(x)\frac{sin(x)}{\cos(x)}]$

$\csc(x)[\frac{\cos(x)\cos(x)+\sin(x)\sin(x)}{\cos(x)}]$

$\csc(x)[\frac{\cos^2(x)+\sin^2(x)}{\cos(x)}]$

$\csc(x)[\frac{1}{\cos(x)}]$

$\csc(x)[\sec(x)]$

$\csc(x)[\csc(\frac{\pi}{2}-x)]$

$\csc(x)\csc(\frac{\pi}{2}-x)$

7 0

3 years ago

When 12 is added to a number the result is 32 less than 3 times a number.<br> What is this number?

neonofarm [45]

X - the number

$x+12=3x-32 \\
x-3x=-32-12 \\
-2x=-44 \\
x=\frac{-44}{-2} \\
x=22$

The number is 22.

7 0

3 years ago

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a mockingbird flaps its wings about fifty thousand four hundred times in an hour round this number to the nearest thousand.

Shtirlitz [24]

Answer: It would be 50,000

Step-by-step explanation: If it was 50,500 - 50,999 it would be : 51,000

Hope it helped out :)

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3 years ago