a) For x = 27:
z = 27-28/2 = -0.5
For x = 31:
z = 31-38/2 = 1.5
From the normal distribution table, P(27 < x < 31) = P(-0.5 < z < 1.5) = P(z < 1.5) - P(z < -0.5) = 0.9332 - 0.3085 = 62.47%
b) For x > 30.2:
z = 30.2-28/2 = 1.1
From the normal distribution table, P(x > 30.2) = P(z > 1.1) = 1 - P(z > 1.1) = 1 - 0.8643 = 13.57%
Answer:
10 times 4 ten thousands = 40 ten thousands
Step-by-step explanation:
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Answer:
0.59375
Step-by-step explanation:
In a uniform distribution the probability that the time t is greater than any given value, X, is:
In this problem, the limits of the distribution are a = 0 and b = 8 minutes.
For X =3.25 minutes:
The probability that a randomly selected passenger has a waiting time greater than 3.25 minutes is 0.59375.
Answer:
456,000,000
Step-by-step explanation:
Sorry if this is wrong :(
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