A kilogram of silver contains 5.58×10²⁴ atoms.
<h3>How to determine the parameter</h3>
From the question given above, the following data were obtained:
- 1 mole of silver = 107.9 g
- Number of atoms in 1 mole of silver = 6.02×10²³ atoms.
- Number of atoms in a kilogram of silver is unknown
Now, we shall convert 1 kg of silver to grams (g).
This can be obtained as follow:
1 kg = 1000g
Therefore, 1 kg of silver is equivalent to 1000g.
Now, let's determine the number of atoms in 1 kg (i.e 1000 g) of silver as follow:
If 107.9 g of silver contains 6.02×10²³ atoms.
Then, 1000 g of silver will contain:
= (1000 × 6.02×10²³) / 107.9
= 5.58×10²⁴ atoms.
Thus, a kilogram of silver contains 5.58×10²⁴ atoms.
Learn more about atoms here:
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Answer:
46
Step-by-step explanation:
n(A U B)= n(A) + n(B) - n(A ∩ B)
n(A)= n(A U B) - n(B) + n(A ∩ B)=49-27+24 =46
Hope, this helps you.
1) Rational because the square root of 16 is 4 and 4 times 4/7 is a rational number (16/7)
2) Irrational because square root of 684 is irrational C
3) The square root of a is irrational so the answer is irrational. The square root of c is rational so the answer is rational.
4) Jacob is wrong because the square root of 5/7 is irrational so the answer to the problem is irrational.
Hi can someone help me for correcting my text
