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aliina [53]
3 years ago
10

The two bases of a trapezoid measure 14 inches and 10 inches respectively. The trapezoid's height is 8 inches. What is the area

of the trapezoid?
192 square inches

1120 square inches

140 square inches

96 square inches
Mathematics
2 answers:
sdas [7]3 years ago
6 0

Answer:

A = 96 inches ^2

Step-by-step explanation:

The area of a trapezoid is given by

A = 1/2 ( b1+b2)h  where b1 and b2 are the bases and h is the height

A = 1/2( 14+10)*8

A = 1/2(24)*8

A = 12*8

A = 96 inches ^2

zheka24 [161]3 years ago
4 0

<h3>\huge\mathfrak\red{❥︎ANSWER}</h3>

<h2>A = 96 square inches..</h2>

<h3>Step-by-step explanation:</h3>

The area of trapezoid is given

A = 1/2 (b1+b2)h where b1 and b2 is base and h is height

A = 1/2 (14+10)*8

A = 1/2 (24)*8

A = 12 * 8

<h3>A = 96 square inches ....</h3>
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A triangular pyramid has a surface area of 174 square feet. It is made up of equilateral triangles with side lengths of 10 feet.
emmainna [20.7K]

Answer:

Slant height = 7.07 ft to nearest hundredth.

Step-by-step explanation:

The slant height = height of one of the triangular sides

Using Pythagoras:

S^2 =  1/2 * 10^2 + 10^2 = 50 ft.

S = √50 = 7.071

6 0
2 years ago
Which ordered pairs are in the solution set of the system of linear inequalities? y &gt; x y &lt; x + 1 (5, –2), (3, 1), (–4, 2)
steposvetlana [31]

To check which ordered pair (point) is in the solution set of the system of given linear inequalities y>x, y<x+1; we just need to plug given points into both inequalities and check if that point satisfies both inequalities or not. If any point satisfies both inequalities then that point will be in solution.

I will show you calculation for (5,-2)

plug into y>x

-2>5

which is clearly false.

plug into y<x+1

-2<5+1

or -2<6

which is also false.

hence (5,-2) is not in the solution.

Same way if you test all the given points then you will find that none of the given points are satisfying both inequalities.

Hence answer will be "No Solution from given choices".

5 0
3 years ago
Read 2 more answers
Will mark brainliest
ikadub [295]

Answer:

3rd choice

Step-by-step explanation:

(7y^6)(2y^-4)^2

= (7y^6)(4y^-8)

Calculate:

(7y^6) * (4y^-8)

28y^-2

Express with a positive exponent:

28 * 1/y^2

8 0
2 years ago
Can someone help me with this question on Prodigy? ​
lions [1.4K]

Answer:

  8 +(3/8)√53 in² ≈ 10.73 in²

Step-by-step explanation:

Given the net of a triangular pyramid with some of the dimensions filled in, you want to find the total surface area.

<h3>Triangle base</h3>

The triangle bases identified by dashed lines will have a length equal to the hypotenuse of the right triangles with legs shown as solid lines. The legs of each of those right triangles are ...

  a = (3 in)/2 = 1.5 in

  b = 2 in . . . . . . shown as the altitude of the triangle

Then the hypotenuse is found using the Pythagorean theorem:

  c² = a² +b²

  c² = 1.5² +2² = 2.25 +4 = 6.25

  c = √6.25 = 2.5

The dashed lines are 2.5 inches long.

<h3>Triangle altitude</h3>

The altitude from the solid horizontal line to the vertex at the bottom of the figure can be found using the fact that all of the outside edge lengths of the net are the same length. That edge length is found as the length of the hypotenuse of the right triangles in the left- and right-sides of the upper portion of the net. Each of those has a leg that is (2.5 in)/2 = 1.25 in and a leg marked as 2 in.

  c² = a² +b²

  c² = 1.25² +2² = 1.5625 +4 = 5.5625

  c = (√89)/4 ≈ 2.358 . . . in

The unmarked altitude of the bottom triangle is then ...

  b² = c² -a²

  b² = 89/16 -1.5² = 53/16

  b = (√53)/4 ≈ 1.820 . . . in

<h3>Surface area</h3>

The surface area of the figure is the sum of the areas of the four triangles that make up the net. Each triangle has an area given by the formula ...

  A = 1/2bh

The left and right triangles have b=2.5, h=2, so they each have an area of ...

  A = 1/2(2.5)(2) = 2.5 . . . . in²

The center triangle has dimensions of b=3, h=2, so an area of ...

  A = 1/2(3)(2) = 3 . . . . in²

The bottom triangle has dimensions of b=3, h=(√53)/4, so an area of ...

  A = 1/2(3)(√53/4) = (3/8)√53 ≈ 2.730 . . . . in²

The total surface area is the sum of the areas of these triangles, so is ...

  A = 2.5 in² +2.5 in² +3 in² +2.73 in² = 10.73 in²

The surface area of the triangular pyramid is (64+3√53)/8 ≈ 10.73 in².

__

<em>Additional comment</em>

Often we work with pyramids that are rotationally symmetrical about a vertical line through the peak. This one is not. The altitude of the bottom triangle in the net is less than the altitude of the other triangles. This short face of the pyramid will tend to be more vertical than the other two lateral faces.

4 0
1 year ago
PLEASE HELP ASAP!!!!!!!!!!!!!!!!!!!!!!!!
expeople1 [14]

Answer:

Step-by-step explanation:

2nd one

6 0
3 years ago
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