Answer:

Step-by-step explanation:
Use the Distance Formula:
![\displaystyle \sqrt{[-x_1 + x_2]^2 + [-y_1 + y_2]^2} = D \\ \\ \sqrt{[6 - 1]^2 + [-7 + 1]^2} = \sqrt{5^2 + [-6]^2} = \sqrt{25 + 36} = \sqrt{61} ≈ 7,810249676 ≈ 8](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Csqrt%7B%5B-x_1%20%2B%20x_2%5D%5E2%20%2B%20%5B-y_1%20%2B%20y_2%5D%5E2%7D%20%3D%20D%20%5C%5C%20%5C%5C%20%5Csqrt%7B%5B6%20-%201%5D%5E2%20%2B%20%5B-7%20%2B%201%5D%5E2%7D%20%3D%20%5Csqrt%7B5%5E2%20%2B%20%5B-6%5D%5E2%7D%20%3D%20%5Csqrt%7B25%20%2B%2036%7D%20%3D%20%5Csqrt%7B61%7D%20%E2%89%88%207%2C810249676%20%E2%89%88%208)
Since we are talking about distance, we ONLY want the NON-NEGATIVE root.
I am joyous to assist you anytime.
9514 1404 393
Answer:
5/9 m/min
Step-by-step explanation:
The depth of the water is 2/5 of the depth of the trough, so the width of the surface will be 2/5 of the width of the trough:
2/5 × 2 m = 4/5 m
Then the surface area of the water is ...
A = LW = (18 m)(4/5 m) = 14.4 m²
The rate of change of height multiplied by the area gives the rate of change of volume:
8 m³/min = (14.4 m²)(h')
h' = (8 m³/min)/(14.4 m²) = 5/9 m/min
Step-by-step explanation:
Starting from the upper left in the clockwise direction:
congruent: no
similar: no
upper right side:
congruent: yes
similar: yes
lower right side:
congruent: no
similar: yes
lower left side:
congruent: yes
similar: yes