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Anuta_ua [19.1K]
1 year ago
7

Which greek geometer founded a philosophical society that devoted itself to study of mathematics​

Mathematics
2 answers:
BlackZzzverrR [31]1 year ago
8 0

Answer:

Pythagoras was the Greek geometer .

<em>Please mark me as the brainliest.</em>

Aleks [24]1 year ago
6 0
Pythagoras was the Greek geometer among the choices given in the question that founded a philosophical society that devoted itself to the study of mathematics
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On a piece of paper, graph this system of inequalities. Then determine which
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The answer is C, Region A.
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Need help !!!!!!!!!!!!!!!!!!!!!!!
stich3 [128]
Answer:  " m∠SRW = 95 ° " .
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Since m∠TRV = 95° ; 

and:  ∠TRV and ∠SRW are vertical angles; 

and:  we are given:  " m∠TRV = 95° " ; 

and:  vertical angles are congruent; 

So, m∠TRV = m∠SRW = 95°  .
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3 years ago
Can someone help me with this? I need to find the points of discontinuity/limits for each of these. I think one point is 4, but
Debora [2.8K]
The answers are shown in the attached image

-------------------------------------------------------------------------

Explanation:

Set the denominator x^4-8x^3+16x^2 equal to zero and solve for x

x^4-8x^3+16x^2 = 0
x^2(x^2-8x+16) = 0
x^2(x-4)^2 = 0
x^2 = 0 or (x-4)^2 = 0
x = 0 or x-4 = 0
x = 0 or x = 4

The x values 0 and 4 make the denominator zero

These x values lead to asymptote discontinuities because the numerator 8x-24 = 8(x-3) has no common factors which cancel with the denominator factors.

There are two vertical asymptotes

Let's see what happens when we plug in a value to the left of x = 0, say x = -1, we'd get
f(x) = (8x-24)/(x^4-8x^3+16x^2)
f(-1) = (8(-1)-24)/((-1)^4-8(-1)^3+16(-1)^2)
f(-1) = -1.28
So as x gets closer and closer to x = 0 from the left side, the f(x) is heading to negative infinity

Now plug in some value to the right of x = 0. I'm going to pick x = 1
f(x) = (8x-24)/(x^4-8x^3+16x^2)
f(1) = (8(1)-24)/((1)^4-8(1)^3+16(1)^2)
f(1) = -1.78 (approximate)
So as x gets closer and closer to x = 0 from the right side, the f(x) is heading to negative infinity

Overall, as x approaches 0 from either the left or right side of x = 0, the y value is heading off to negative infinity

---------------------

Repeat for values to the left and right of x = 4
We can't use x = 1 as it turns out that x = 3 is a root
But we can use something like x = 3.5 to find that...
f(x) = (8x-24)/(x^4-8x^3+16x^2)
f(3.5) = (8(3.5)-24)/((3.5)^4-8(3.5)^3+16(3.5)^2)
f(3.5) = 1.31 approx
So as x gets closer to x = 4 from the left, y is getting closer to positive infinity

Plug in x = 5 to find that
f(x) = (8x-24)/(x^4-8x^3+16x^2)
f(5) = (8(5)-24)/((5)^4-8(5)^3+16(5)^2)
f(5) = 0.64
which has the same behavior as the left side

So overall, as we approach x = 4, the y value is heading off to positive infinity

Again everything is summarized in the image attachment

Note: you could make a table of more values but they would effectively say what has already been said. It would be redundant busy work. However, its always good practice for function evaluation. 

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2 years ago
Write the quadratic equation in standard form please<br> -5x^2-6x=-1+2x
slava [35]

Answer:

-5x^2-8x+1=0

Hope this helps!!

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115 is what percent of 200?
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57.5 is the answer. Because think of 200 as 100% and 15 out of a hundered is ______. Right.
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