(12 divided by 3) 2 – (18 divided by 3 2)) < (4 divided by 2)
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Given:
In ΔJKL, m∠L=90°, JL = 80, KJ = 89, and LK = 39.
To find:
The value of sine of ∠J.
Solution:
In a right angle triangle,
In triangle JKL,
Therefore, the value of sine of ∠J is about 0.44.