1)
x^2 + (3y/2z) = 7
2x^2z + 3y = 14z
3y = 14z - 2x^2z
3y = 2z(7 - x^2)
y = 2/3(z)(7 - x^2)
2)
(3zx^4) /(5+z) = 2y
3zx^4 = 2y(5+z)
3zx^4 = 10y + 2yz
Answer:
x=-2
Step-by-step explanation:
I am assuming 33 is B^(2/3) times B^(1/2)
See the following image
Answer:
67 mm
Step-by-step explanation:
use area of a trap formula:
b1+b2 /2*h
b1=base
b2=base
h=height
in our case it was, 8.2+5.2/2*10
67
1: if u use the same measures they will be congruent angles.
2: because the segment is being cut in half.
3: their has to be an intersection in the arcs<span />