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Wewaii [24]
3 years ago
9

What is another way to name 1/4

Mathematics
1 answer:
baherus [9]3 years ago
7 0

° ∪ ° Hi there!

I will give you a few different ways to name \frac{1}{4}

Simply, you can divide the fraction's numerator by it's denominator to get the simple answer of 0.25.

1 ÷ 4 = 0.25

If you were looking for a decimal answer, 0.25 would be just right.

Looking for a percent? No problem!

All you do is take your numerator, divide it by its denominator and you'd get 0.25 AGAIN. But don't throw this decimal number out the window! Multiply it by 100 and see what you get.

0.25 × 100 = 25

Now that we have a whole number of 25, put a percent sign right next to it so it equals 25%!

There is 1 more way I would like to show you.

You could double the numerator and the denominator's size of the fraction to get 2 over 8 :)

It will still equal 0.25, or 25%!

If you wanted to make this fraction even BIGGER, you can multiply the numerator and the denominator's size by whatever you want, as long as they're the same number your multiplying by!

↑   ↑   ↑  Hope this helps! :D

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Answer:

y = 1/3

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
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Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

2x - 9y = 11

<em>x</em> = 7

<u>Step 2: Evaluate</u>

  1. Substitute in <em>x</em>:                                                                                                  2(7) - 9y = 11
  2. Multiply:                                                                                                             14 - 9y = 11
  3. [Subtraction Property of Equality] Subtract 14 on both sides:                       -9y = -3
  4. [Division Property of Equality] Divide -9 on both sides:                                 y = 1/3
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2 years ago
Find the indicated values, where g(t)=t^2-t and f(x)=1+x f(2g(1)
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g(t)=t^2-t\\\\f(x)=1+x\\\\f(2g(1))=?\\\\g(1)=\\_{\text{put t=1 to the equation of g(t)}}\\\\=1^2-1=1-1=0\\---------------\\2g(1)=2(0)=0\\\\f(2g(1))=\\_{\text{put x-0 to the equation of f(x)}}\\\\=1+0=1\\\\Answer:\ f(2g(1))=1

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3 years ago
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$720 in one week

Step-by-step explanation:

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(–4c2 + 7cd + 8d) + (–3d + 8c2 + 4cd) =
BabaBlast [244]

Answer:

4c² + 11cd + 5d

Step-by-step explanation:

(–4c2 + 7cd + 8d) + (–3d + 8c2 + 4cd)

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8c²-4c²+7cd + 4cd + 8d - 3d

= 4c² + 11cd + 5d

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