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PolarNik [594]
3 years ago
9

You believe the population is normally distributed and you know the standard deviation is σ = 6.9 σ = 6.9 . You obtain a sample

mean of M = 64.4 M = 64.4 for a sample of size n = 32 n = 32 . What is the critical value for this test?
Mathematics
1 answer:
kaheart [24]3 years ago
8 0

The critical values is 16

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(x^2+y)(x^4y^3)/xy^2
r-ruslan [8.4K]

Answer:

(x^2+y)x^3 y^5

Step-by-step explanation:

(x^2 + y)x^4 y^3 / x y^2

(x^2 + y)x^4 - 1 y^3 * y^2

(x^2 + 7)x^3 y^3 * y^2

(x^2 + y)x^3 y^3 +^2

(x^2 + y)x^3 y^5

6 0
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Find the least common multiple of 7,9 and 21
lawyer [7]
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3 years ago
Helpp me pleasee (algebra)
antiseptic1488 [7]

Answer:

Step-by-step explanation:

answer = 1/2 r + m

m = 7

r = 8

answer = 1/2 * 8 + 7

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8 0
3 years ago
13x-7y+4x
Vinvika [58]

Answer:

17−7

Step-by-step explanation:

Hope this helped good luck in your work!

4 0
3 years ago
The population of deer forest is currently 800 individuals. Scientists predict that this population will grow at a rate of 20 pe
jonny [76]

Answer:

<em>C. 3.8 years</em>

Step-by-step explanation:

<u>Exponential Growth </u>

The natural growth of some magnitudes can be modeled by the equation:

P(t)=P_o(1+r)^t

Where P is the actual amount of the magnitude, Po is its initial amount, r is the growth rate and t is the time.

The actual population of deer in a forest is Po=800 individuals. It's been predicted the population will grow at a rate of 20% per year (r=0.2).

We have enough information to write the exponential model:

P(t)=800(1+0.2)^t

P(t)=800(1.2)^t

It's required to find the number of years required for the population of deers to double, that is, P = 2*Po = 1600. We need to solve for t:

800(1.2)^t=1600

Dividing by 800:

(1.2)^t=1600/800=2

Taking logarithms:

t\log 1.2=\log 2

Dividing by log 1.2:

t=\frac{\log 2}{ \log 1.2}

Calculating:

t = 3.8 years

Answer: C. 3.8 years

6 0
3 years ago
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