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Inessa [10]
3 years ago
9

1. Find the areas of these trapezia by first finding x using

Mathematics
1 answer:
Stels [109]3 years ago
7 0

Answer:

Concept: Mathematical Computation

  1. To perform Pythagoras theorem you must use the following equation.
  2. {a}^{2}  +  {b}^{2}  =  {c}^{2}
  3. Where a and b can be any side by c must be the hypotenuse which is the longest side of the triangle.
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Solve for x by simplifying both sides of the equation , then isolating the variable 
your answer is x=3/4
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Convert the given radian measure to a degree measure. 1.1 pi a. Negative 99 degrees b. Negative 198 degrees c. 99 degrees d. 198
irina1246 [14]

d is the right ancer

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3 years ago
What is the average rate of change for f(x)+2^x+2 over interval −1 ≤ x ≤ 1
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Answer:

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Step-by-step explanation:

7 0
2 years ago
Each week, Heather’s company has $5000 in fixed costs plus an additional $250 for each system produced. The company is able to p
kvv77 [185]

The question is an illustration of composite functions.

  • Functions c(n) and h(n) are \mathbf{c(n) = 5000 + 250n} and \mathbf{n(h) = 5h}
  • The composite function c(n(h)) is \mathbf{c(n(h)) = 5000 + 1250h}
  • The value of c(n(100)) is \mathbf{c(n(100)) = 130000}
  • The interpretation is: <em>"the cost of working for 100 hours is $130000"</em>

The given parameters are:

  • $5000 in fixed costs plus an additional $250
  • 5 systems in one hour of production

<u>(a) Functions c(n) and n(h)</u>

Let the number of system be n, and h be the number of hours

So, the cost function (c(n)) is:

\mathbf{c(n) = Fixed + Additional \times n}

This gives

\mathbf{c(n) = 5000 + 250 \times n}

\mathbf{c(n) = 5000 + 250n}

The function for number of systems is:

\mathbf{n(h) = 5 \times h}

\mathbf{n(h) = 5h}

<u>(b) Function c(n(h))</u>

In (a), we have:

\mathbf{c(n) = 5000 + 250n}

\mathbf{n(h) = 5h}

Substitute n(h) for n in \mathbf{c(n) = 5000 + 250n}

\mathbf{c(n(h)) = 5000 + 250n(h)}

Substitute \mathbf{n(h) = 5h}

\mathbf{c(n(h)) = 5000 + 250 \times 5h}

\mathbf{c(n(h)) = 5000 + 1250h}

<u>(c) Find c(n(100))</u>

c(n(100)) means that h = 100.

So, we have:

\mathbf{c(n(100)) = 5000 + 1250 \times 100}

\mathbf{c(n(100)) = 5000 + 125000}

\mathbf{c(n(100)) = 130000}

<u>(d) Interpret (c)</u>

In (c), we have: \mathbf{c(n(100)) = 130000}

It means that:

The cost of working for 100 hours is $130000

Read more about composite functions at:

brainly.com/question/10830110

5 0
3 years ago
~Please halp~ <br> Also drawings of mine UwU
liubo4ka [24]

Answer:

DAM.NNN U DREW DAT

Step-by-step explanation:

T.FFFF

3 and 5 are corresponding

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