The grams of the sugar in 125 g of the drink is calculated as below
%M/m) = mass of the solute (sugar)/ mass of the solvent(drink) x100
let the mass of the solute(sugar) be represented by y
convert % into fraction by dividing by 100 = 10.5/100
10.5/100 = y/125
by cross multiplication
100y =1312.5
divide both side by 100
y=13.125 grams
Answer:
The oxidation state of silver in
is
.
The oxidation state of sulfur in
is
.
Explanation:
The oxidation states of atoms in a compound should add up to zero.
<h3>Ag₂O</h3>
There are two silver
atoms and one oxygen
atom in one formula unit of
. Therefore:
.
The oxidation state of oxygen in most compounds (with the exception of peroxides and fluorides) is
. Silver oxide
isn't an exception. Therefore:
.
Solve this equation for the (average) oxidation state of
:
.
<h3>SO₂</h3>
Similarly, because there are one sulfur
atom and two oxygen
atoms in each
molecules:
.
The oxidation state of
in
is also
, not an exception, either.
Therefore:
.
Solve this equation for the oxidation state of
here:
.
Hello,
The answer is "<span>behaviors and properties of metals".
Reason:
</span>The answer is the study of behaviors and properties of metals.
If you need anymore help feel free to ask me!
Hope this helps!
~Nonportrit
the Calorimetry relationships you can find the amount of water in the calorimeter is m = 21.3 g
given parameters
- Lead mass M = 200.0 g
- Initial lead temperature T₁ = 176.4ºC
- Specific heat of Lead
= 0.129 J / g ºC - Sspecific heat of water
= 4.186 J / g ºC - Initial water temperature T₀ = 21.7ºC
- Equilibrium temperature T_f = 56.4ºC
to find
The body of water
Thermal energy is the energy stored in the body that can be transferred as heat when two or more bodies are in contact. Calorimetry is a technique where the energy is transferred between the body only in the form of heat and in this case the thermal energy of the lead is transferred to the calorimeter that reaches the equilibrium that the thematic energy of the two is equal
Q_{ceded} = Q_{absorbed}
Lead, because it is hotter, gives up energy
Q_{ceded} = M c_{e Pb} (T₁ - T_f)
The calorimeter that is colder absorbs the heat
Q_{absrobed} = m c_{e H_2O} (T_f - T₀)
where M and m are the mass of lead and water, respectively, c are the specific heats, T₁ is the temperature of the hot lead, T₀ the temperature of cold water and T_f the equilibrium temperature
M c_{ePb} (T₁ - T_f) = m c_{eH2O} (T_f - T₀)
m = 
let's calculate
m = 
m = 3096 / 145.25
m = 21.3 g
Using the Calorimetry relationships you can find the amount of water in the calorimeter is:
m = 21.3 g
learn more about calorimetry here:
brainly.com/question/15073428