Hello!
On the periodic table, as we go down the periodic table, the ionization energy decreases, but as we go across the periodic table (left to right), the ionization increases.
On the periodic table, lithium (Li) is located in column one, beryllium (Be) is located in column two, and (B) boron is located in column 13. As stated above, when we go across the periodic table (left to right), the ionization increases.
Therefore, the element with the highest ionization energy is Boron, or symbol B on the period table.
Answer/ explanation :
Protist can be multicellular or unicellular organisms
Plants are all multicellular and also exhibit cellular differentiation.
Protist can be autotroph, heterotrophic or decomposer
Plants are only autotrophs because they manufacture their own food through photosynthesis
Protists are microscopic, more diverse and abundant in nature
Plants are big and complex in nature
Nuclear DNA strands in plants are of higher complexity than those of protist
Plants require oxygen for cellular respiration process unlike protist which can be aerobic and some other species facultative anaerobic
Plants only can reproduce asexually through bulbs and tubers as in yam, potatoes while protists reproduce either sexually through meiosis or asexually through simple cell division.
<u>Answer:</u> The freezing point of solution is 2.6°C
<u>Explanation:</u>
To calculate the depression in freezing point, we use the equation:

Or,

where,
= 
Freezing point of pure solution = 5.5°C
i = Vant hoff factor = 1 (For non-electrolytes)
= molal freezing point depression constant = 5.12 K/m = 5.12 °C/m
= Given mass of solute (anthracene) = 7.99 g
= Molar mass of solute (anthracene) = 178.23 g/mol
= Mass of solvent (benzene) = 79 g
Putting values in above equation, we get:

Hence, the freezing point of solution is 2.6°C
Answer:i read it Explanation: