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3 years ago

2(m-3)+7<21 PLEASE HELP!!!

Mathematics

1 answer:

Contact [7]3 years ago

4 0

Simplify. Distribute 2 to all terms within the parenthesis

2(m -3) = 2m - 6

Simplify. Combine like terms

2m - 6 + 7 < 21

2m + 1 < 21

Isolate the m. Subtract 1 from both sides

2m + 1 (-1) < 21 (-1)

2m < 20

Isolate the m. Divide 2 from both sides

2m/2 < 20/2

m < 20/2

m < 10

m < 10 is your answer

hope this helps

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If DF = 35 and EF = 12, what is DE?<br><br> ANSWER QUICK

Sholpan [36]

Straight lines can be divided into different segments

The value of DE is 23 units

We have:

$DF = 35$

$EF = 12$

Segment DF and EF have the same endpoint.

This means that, point E is located on segment DF

So, we have:

$DF = DE + EF$

Substitute known values

$35 = DE + 12$

Collect like terms

$DE = 35- 12$

$DE =23$

Hence, the value of DE is 23 units

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brainly.com/question/15754081

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2 years ago

Use the Law of Cosines to find the missing angle. In triangle JKL, j=3in., k=4in., and l=2.89., find mJ

slega [8]

Using the law of cosine for Triangle KJL, we can write:

$j^{2} = k^{2} + l^{2}-2(k)(l)cos(J) \\ \\ 
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Using the values of k,j and l, we can write:

$cos(J)= \frac{ 4^{2} + (2.89)^{2} - 3^{2} }{2(4)(2.89)} \\ \\ 
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So option B gives the correct answer

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3 years ago

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Dovator [93]

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Korolek [52]

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