Answer:
y = x - 5
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m = (y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁ ) =( 8, - 3) and (x₂, y₂ ) = (0, - 5)
m = =
=
Note the line crosses the y- axis at (0, - 5 ) ⇒ c = - 5
y = x - 5 ← equation of line
Answer:
Please refer to the attached graph
Step-by-step explanation:
Knowing the following:
X = amount of money donated to the city youth fund
Y = amount of money donated to the educational growth foundation
We can write the statements in form of equations:
"Will donate up to $500, the money will be divided between two charities"
(a)
"The amount donated to the educational growth foundation to be at least four times the amount donated to the city youth fund"
(b)
If we graph both equations we can see the area where both conditions are met (see graph attached)
Where the blue line is (a) and the red line is (b)
Shaded area represent all the possible solutions for the donations, for example:
X=100 and Y=400 or
X=50 and Y=200, etc.
9514 1404 393
Answer:
x = 1 or 5
Step-by-step explanation:
The notion of "cross-multiplying" is the idea that the numerator on the left is multiplied by the denominator on the right, and the numerator on the right is multiplied by the denominator on the left. This looks like ...
Then the solution proceeds by eliminating parentheses, and solving the resulting quadratic equation.
_____
<em>Comment on "cross multiply"</em>
Like a lot of instructions in Algebra courses, the idea of "cross multiply" describes <em>what the result looks like</em>. It doesn't adequately describe how you get there. The <em>one and only rule</em> in solving Algebra problems is "<em>whatever is done to one side of the equation must also be done to the other side of the equation</em>." If you multiply one side by one thing and the other side by a different thing, you are violating this rule.
What looks like "cross multiply" is really "<em>multiply by the product of the denominators</em> and cancel like terms from numerator and denominator." Here's what that looks like with the intermediate steps added.