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Serjik [45]
3 years ago
10

Use the Law of Cosines to find the missing angle. In triangle JKL, j=3in., k=4in., and l=2.89., find mJ

Mathematics
2 answers:
slega [8]3 years ago
8 0
Using the law of cosine for Triangle KJL, we can write:

j^{2} = k^{2} + l^{2}-2(k)(l)cos(J)  \\  \\ 
2(k)(l)cos(J)=k^{2} + l^{2}- j^{2} \\  \\ 
cos(J)= \frac{k^{2} + l^{2}- j^{2}}{2(k)(l)}

Using the values of k,j and l, we can write:

cos(J)= \frac{ 4^{2} + (2.89)^{2} - 3^{2} }{2(4)(2.89)}  \\  \\ 
cos(J)= 0.664 \\  \\ 
J= cos^{-1}(0.664) \\  \\ 
J=48.39

Rounding to nearest integer, the measure of angle J will be 48 degrees.
So option B gives the correct answer
sattari [20]3 years ago
3 0
Answer: option B. 48°

Explanation:


1) Data:
side j: 3 in

side k: 4in
side l: 2.89 in
angle J: ?

2) Law of cosines

j² = k² + l² - 2kl cos(J)

⇒ 3² = 4² + (2.89)² - 2(4)(2.89)cos(J)

⇒ cos(J) = [16 + 8.3521 - 9] / (23.12)

⇒cos(J) = 0.66402
⇒ J = arc cosine (0.66402) ≈ 48.39°
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1
Sergeu [11.5K]

Answer:

9C=5(F-32)

Step-by-step explanation:

The equation which can convert the temperature from degree Celsius into degree Fahrenheit is given as under

9C=5(F-32)

We can solve it further for F as

9C=5F-5 \times 32

9C=5F-160

9C+160=5F

Dividing both sides by 5 we get

\frac{9C}{5}+32=F

F=\frac{9C}{5}+32

Now substituting values of C in this equation will give us the corresponding values of F

Ex : C=1

F=\frac{ 9\times 1}{5}+32

F=\frac{ 9+160}{5}

F=\frac{ 169}{5}

Hence 1 degree Celsius is \frac{ 169}{5} degree Fahrenheit

4 0
3 years ago
0.6x-0.1=0.5x+2 <br> The solution set is {_} <br><br> PLEASE PLEASE PLEASE EXPLAIN HOW
timurjin [86]

Answer:

21

Step-by-step explanation:

Step 1:

0.6x - 0.1 = 0.5x + 2      Equation

Step 2:

0.1x - 0.1 = 2     Subtract 0.5x on both sides

Step 3:

0.1x = 2.1     Add 0.1 on both sides

Step 4:

x = 2.1 ÷ 0.1    Divide

Ansewr:

x = 21

Hope This Helps :)

3 0
3 years ago
Solve for x and y please help!!
Pie

Answer:

the answer is

y= 26.57

x= 35.09

5 0
3 years ago
Which models show 40%? Check all that apply. A model with 4 shaded sections and 6 unshaded sections. A model with 40 shaded sect
Amanda [17]

Answer:

A model with 4 shaded sections and 6 unshaded sections.

A model with 40 shaded sections and 60 unshaded sections.

Step-by-step explanation:

Required:

Which models shows 40%

(a) 4 shaded and 6 unshaded

First, we calculate the total sections

Total = 4 + 6

Total = 10

The percentage of the shaded section is:

Shaded = \frac{4}{10} * 100\%

Shaded = 0.4 * 100\%

Shaded = 40\%

(b) 40 shaded and 60 unshaded

First, we calculate the total sections

Total = 40 + 60

Total = 100

The percentage of the shaded section is:

Shaded = \frac{40}{100} * 100\%

Shaded = 0.4 * 100\%

Shaded = 40\%

(c) 2 shaded and 8 unshaded

First, we calculate the total sections

Total = 2 + 8

Total = 10

The percentage of the shaded section is:

Shaded = \frac{2}{10} * 100\%

Shaded = 0.2 * 100\%

Shaded = 20\%

<em>Hence, (a) and (b) shows 40%</em>

8 0
3 years ago
Read 2 more answers
Fifteen percent of 168
allsm [11]

\large\text{Hey there!}


\rm{15\%\ of\ 168}\\\\\rm{= 15\% \times 168} \\\\\rm{= \dfrac{15}{100}\times 168}\\\\\rm{= \dfrac{15}{100}\times \dfrac{168}{1}}\\\\\rm{=\dfrac{15\times168}{100\times1}}\\\\\rm{= \dfrac{2,520}{100}}\\\\\rm{= 25.2}


\huge\text{Therefore, your answer should be: }

\huge\boxed{\frak{25.2}}\huge\checkmark


\huge\text{Good luck on your assignment \& enjoy your day!}


~\frak{Amphitrite1040:)}

8 0
1 year ago
Read 2 more answers
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