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3 years ago

12

A vehicle uses 1 1/8 of gasoline to travel 13 1/2 miles. At this rate, how many miles can the vehicle travel per gallon of gasol

ine.

1 answer:

nydimaria [60]3 years ago

3 0

$\sqrt[11.8]{13.5}$ that’s wwha YaI’m tsftufug

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PLEASE HELP WITH THIS QUESTION

Karolina [17]

Answer:

a) 0.8( 8/10 gives 0.8)

b)0.7( if it was 7/100 it would have been

0.07)

c)3.5( by converting mixed fractions to improper fractions, that is, 3×2+1 and having the same denominator 2… we get 7/2… for the purpose of converting it to decimal, 7×5/2*5= 35/10… by moving one decimal place to the left, we get 3.5)

D) 2.5 ( the same way as c) 5*5/2*5: 25/10 or you can make it to be 5*50/2*50: 250/100 which still gives 2.5)

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3 years ago

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Expand and simplify (2x + 3) (x + 7)

RUDIKE [14]

Answer:

$2x^{2} +17x+21$

Step-by-step explanation:

multiply the 2x by x and 7 and then multiply 3 by x and 7. you will get 2 $x^{2}$ +14x+3x+21. combine like terms so add 14x to 3x and thats the only like trerms in the equation. so 2x^2+17x+21

5 0

1 year ago

3) 8а - 5а answer please

goldfiish [28.3K]

Answer:

8a-5a=3a

Step-by-step explanation:

8-5=3, basically simple subtraction, just bring the variable to the other side.

3 0

3 years ago

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What is the surface aria of a sphere

nalin [4]

You could go to the website "answers" thats where i usaully get help from

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3 years ago

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PLEASE ANSWER THIS ASAP

Arisa [49]

Answer:

The equation of line passes through $(4,-1)$ and perpendicular to the graph $y=\frac{7}{2}x-\frac{3}{2}$ is $y=\frac{-2x}{7}+\frac{1}{7}$

Step-by-step explanation:

Given point is $(4,-1)$ and equation of line is $y=\frac{7}{2}x-\frac{3}{2}$

Let the slope of line that passes through point $(4,-1)$ is $m_1$

And slope of line $y=\frac{7}{2}x-\frac{3}{2}$ is $m_2=\frac{7}{2}$ . As it is in the form of $y=mx+c$

We know the relation between slope of perpendicular line are given by

$m_1\times m_2=-1\\And\ m_1=\frac{-1}{m_2}$

So, the slope $m_1=\frac{-1}{\frac{7}{2}}=\frac{-2}{7}$

Now, we can write the equation of line having point $(4,-1)$ and slope $\frac{-2}{7}$

$(y-y_1)=m(x-x_1)\\\\(y-(-1))=\frac{-2}{7}(x-4)\\\\y+1=\frac{-2x}{7}-(\frac{2\times -4}{7})\\ \\y+1=\frac{-2x}{7}+\frac{8}{7}\\\\y=\frac{-2x}{7}+\frac{8}{7}-1\\\\y=\frac{-2x}{7}+\frac{8-7}{7}\\\\y=\frac{-2x}{7}+\frac{1}{7}$

So, the equation of line passes through $(4,-1)$ and perpendicular to the graph $y=\frac{7}{2}x-\frac{3}{2}$ is $y=\frac{-2x}{7}+\frac{1}{7}$

3 0

3 years ago