3 years ago

Consider this linear system:

Mathematics

2 answers:

Galina-37 [17]3 years ago

7 0

Answer: A

Step-by-step explanation:

points

Ipatiy [6.2K]3 years ago

4 0

Answer: A) (2, 4) :))

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Anyone know how to solve this??

Tom [10]

$Given : \frac{(x^\frac{2}{5})^9\;.\;(x^\frac{-4}{15})}{x^\frac{1}{3}}$

$\implies {(x^\frac{18}{5})\;.\; (x^\frac{-4}{15})}\;.\;(x^\frac{-1}{3})$

$\implies x^(^\frac{18}{5} ^-^\frac{4}{15}^-^\frac{1}{3}^)$

$\implies x^(^(^\frac{54 - 4}{15}^)^-^\frac{1}{3}^) = x^(^(^\frac{50}{15}^)^-^\frac{1}{3}^) = x^(^(^\frac{10}{3}^)^-^\frac{1}{3}^) = x^(^\frac{9}{3}^) = x^3$

$\implies x^k = x^3$

$\implies k = 3$

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vlabodo [156]

8h + 10 or 10 + 8h

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Answer:

23%

Step-by-step explanation:

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