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liraira [26]
3 years ago
8

How long will it take Karen to drive 975 miles, if her average speed is 65 miles per hour? Write a formula

Mathematics
2 answers:
ivann1987 [24]3 years ago
7 0
Hope this helps but the answer is 15 hours because 975/65=15
irga5000 [103]3 years ago
6 0
It'll take her 15 hours.
Formula:   975= 65x 
Where x represents hours
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Answer:

Perpendicular

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Step-by-step explanation:

First one : the lines intersect and they form right angles

The second one : they don't intersect and appear on separate planes

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3 years ago
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Plzzz help 100+ points
o-na [289]

Answer:

1) 95% is the minimum

Step-by-step explanation:

If 5 tests were taken, and 100 pts each, and he received 77/100 on all 5 tests, then his grade would be 385/500 being 77%. Add another 100 pts to the denominator (for the last test) and 95 to the numerator, equaling 480/600, or 80%.

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3 years ago
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Question:
faltersainse [42]

Answer:

The probability that a ship that is declared defecive is sound is 0.375

Step-by-step explanation:

Let P(A|B) denote the conditional probability of A given B. We will make use of the equation

P(A|B) = P(A) × P(B|A) / P(B)

We have the probabilities:

  • P(Declared Defective (detected) | Defective) = 0.95
  • P(not Detected | Defective) = 1-0.95=0.05
  • P(Declared Sound | Sound) = 0.97
  • P(Declared Defective |Sound) = 1-0.97=0.03
  • P(Defective)=0.05
  • P(Sound)= 1- 0.05 = 0.95

We can calculate:

P(Declared Defective)= P(Detected | Defective)×P(Defective) + P(Declared Defective |Sound) ×P(Sound) = 0.95×0.05 + 0.03×0.95=0.076

P(S | Declared Defective) =

(P(Sound) × P(Declared Defective | Sound)) / P(Declared Defective)

=0.95×0.03 /0.076 =0.375

3 0
2 years ago
Suppose that an airline overbooks seats on their flights. In particular, it sells 300 tickets for a flight when there are only 2
vladimir1956 [14]

Using the <u>normal approximation to the binomial</u>, it is found that there is a 0.994 = 99.4% probability that we will have enough seats for everyone who shows up.

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.  
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
  • The binomial distribution is the probability of <u>x successes on n trials</u>, with <u>p probability</u> of a success on each trial. It can be approximated to the normal distribution with \mu = np, \sigma = \sqrt{np(1-p)}.

In this problem:

  • 15% do not show up, so 100 - 15 = 85% show up, which means that p = 0.85.
  • 300 tickets are sold, hence n = 300.

The mean and the standard deviation are given by:

\mu = np = 300(0.85) = 255

\sigma = \sqrt{np(1-p)} = \sqrt{300(0.85)(0.15)} = 6.185

The probability that we will have enough seats for everyone who shows up is the probability of at most <u>270 people showing up</u>, which, using continuity correction, is P(X \leq 270 + 0.5) = P(X \leq 270.5), which is the <u>p-value of Z when X = 270.5</u>.

Z = \frac{X - \mu}{\sigma}

Z = \frac{270.5 - 255}{6.185}

Z = 2.51

Z = 2.51 has a p-value of 0.994.

0.994 = 99.4% probability that we will have enough seats for everyone who shows up.

A similar problem is given at brainly.com/question/24261244

8 0
2 years ago
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melomori [17]

It's an equilateral triangle. The angles have measure 60°.

Therefore we have the equations:

6x + 6 = 60        <em>subtract 6 from both sides</em>

6x = 54     <em>divide both sides by 6</em>

x = 9

5y + 10 = 60      <em>subtract 10 from both sides</em>

5y = 50      <em>divide both sides by 5</em>

y = 10

7 0
3 years ago
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