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Arisa [49]
4 years ago
5

Can someone help me? I’m dying, math is so difficult for me, this is algebra

Mathematics
1 answer:
RoseWind [281]4 years ago
8 0

The answer is above.

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Save me the headache
maxonik [38]

(9\sin2x+9\cos2x)^2=81

Taking the square root of both sides gives two possible cases,

9\sin2x+9\cos2x=9\implies\sin2x+\cos2x=1

or

9\sin2x+9\cos2x=-9\implies\sin2x+\cos2x=-1

Recall that

\sin(\alpha\pm\beta)=\sin\alpha\cos\beta\pm\cos\alpha\sin\beta

If \alpha=2x and \beta=\dfrac\pi4, we have

\sin\left(2x+\dfrac\pi4\right)=\dfrac{\sin2x+\cos2x}{\sqrt2}

so in the equations above, we can write

\sin2x+\cos2x=\sqrt2\sin\left(2x+\dfrac\pi4\right)=\pm1

Then in the first case,

\sqrt2\sin\left(2x+\dfrac\pi4\right)=1\implies\sin\left(2x+\dfrac\pi4\right)=\dfrac1{\sqrt2}

\implies2x+\dfrac\pi4=\dfrac\pi4+2n\pi\text{ or }\dfrac{3\pi}4+2n\pi

(where n is any integer)

\implies2x=2n\pi\text{ or }\dfrac\pi2+2n\pi

\implies x=n\pi\text{ or }\dfrac\pi4+n\pi

and in the second,

\sqrt2\sin\left(2x+\dfrac\pi4\right)=-1\implies\sin\left(2x+\dfrac\pi4\right)=-\dfrac1{\sqrt2}

\implies2x+\dfrac\pi4=-\dfrac\pi4+2n\pi\text{ or }-\dfrac{3\pi}4+2n\pi

\implies2x=-\dfrac\pi2+2n\pi\text{ or }-\pi+2n\pi

\implies x=-\dfrac\pi4+n\pi\text{ or }-\dfrac\pi2+n\pi

Then the solutions that fall in the interval [0,2\pi) are

x=0,\dfrac\pi4,\dfrac\pi2,\dfrac{3\pi}4,\pi,\dfrac{5\pi}4,\dfrac{3\pi}2,\dfrac{7\pi}4

5 0
3 years ago
Read 2 more answers
Simplify the expression x(2x + 3) + (x - 3)(x - 4)
Art [367]
<span>x(2x + 3) + (x - 3)(x - 4)
=2x^2 + 3x +x^2 -3x -4x + 12
=3x^2 - 4x  + 12</span>
6 0
3 years ago
A number has only 1 factor pair. One of its factors is twice the other factor. What is the number? Explain.
Mrrafil [7]
<h3>Answer:  2</h3>

========================================================

Explanation:

If a number only has one factor pair, then that number must be prime. This is because prime numbers only have factors of 1 and the number itself.

For instance, the value 7 is prime because the only factors of this are 1 and 7.

For something like the number 32, it is composite and not prime because it has the factors {1,2,4,8,16,32} and it leads to these three factor pairs: 1*32, 2*16, 4*8. This is one example showing why the answer isn't composite.

-----------

Let's say that p is the unknown prime we want to find. The factors of this are 1 and p. We're told that "one of the factors is twice the other factor", so that must mean p = 2*1 = 2. We can see that 2 is twice that of 1.

8 0
3 years ago
How do you solve #3? The one that is incorrect.
Sunny_sXe [5.5K]
Infinite they’re all multiples, so they are the same line
7 0
3 years ago
4. Why does Miss Maudie only have two small cakes instead of three
Rudiy27

Answer:

B

Step-by-step explanation:

She only has two cakes because that's all she bought.

8 0
4 years ago
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