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Vladimir79 [104]
3 years ago
6

Need help ASAP!!!! last minute hw i need to do

Mathematics
1 answer:
vazorg [7]3 years ago
6 0

Our range is all set of y-values. Focus on y-value only.

Our range is {1,5,-1,7,-2}

So the answer is 1, 5,-1,7 and 2

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4. The sum of iwo numbers is 36. Twice the first
Ludmilka [50]

Answer:

  14 and 22

Step-by-step explanation:

If x is the first number, then 36-x is the second. We are told that ...

  2x -(36-x) = 6 . . . . twice the first less the second is 6

  3x = 42 . . . . . . . . . add 36

  x = 14

  (36 -x) = 22

The numbers are 14 and 22.

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3 years ago
The product of 41 and a
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Answer:41a

Step-by-step explanation: when you multiply a number and a variable it will give you the number and the variable which is the unknown

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How would you describe the slice that created the rectangular
Lena [83]

Answer:

The answer is perpendicular to the base.

Step-by-step explanation:

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A bag contains 3 red marbles, 4 blue marbles and 5 yellow marbles. In this experiment you reach in the bag, select a marble, rec
yanalaym [24]

Answer:

1/9

Step-by-step explanation:

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3 0
3 years ago
The circle given by : x^2 + y^2 - 6y - 12 = 0 can be written as:
deff fn [24]

Step-by-step explanation:

Given equation of circle is,

{x}^{2}  +  {y}^{2}  - 6y - 12 = 0 \\ by \: compairing \: it \: with \:   \\ {x}^{2}  +  {y}^{2}   + 2gx + 2fy = 0 \: we \: get \\2 g = 0 \: or \: g = 0 \\ 2f=  - 6 \\ or \: f=  - 3 \\ c =  - 12

again the another form of circle is,

{x}^{2}  +  {(y - k)}^{2}  = 21 \\ or \:  {x}^{2}  + {y}^{2}  - 2ky +  {k}^{2}  - 21 = 0 \\ by \: compairing \:it \: with \:  \\ {x}^{2}  +  {y}^{2}   + 2gx + 2fy = 0 \: we \: get  \\ g = 0 \\f =  - k \\ c =  {k}^{2}  - 21

now equating the values of f in both equations,

-k=-3

i.e. k=3

therefore k=3

4 0
3 years ago
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