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Alla [95]
2 years ago
13

Evaluate 2/6.341+3/9.222

Mathematics
1 answer:
Burka [1]2 years ago
4 0

The evaluation of the given improper fraction is  0.64071.

<h3>How do we evaluate fractions?</h3>

We can evaluate improper fractions by simply determining the L.C.M of the denominators and equating it to the numerators.

Given that:

=\mathbf{\dfrac{2}{6.341} +\dfrac{3}{9.222} }

= The L.C.M for 6.341 and 9.222 is 58.476702.

So, we have:

\mathbf{= \dfrac{18.444}{58.476702} +\dfrac{19.023}{58.476702} }

\mathbf{= \dfrac{18.444+19.023}{58.476702} } }

\mathbf{= \dfrac{37.467}{58.476702} } }

= 0.64071

Learn more about calculating improper fractions here:

brainly.com/question/387381

#SPJ1

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3 years ago
Find the slope <br><br> (3, 8) and (2, 10)
polet [3.4K]

Answer:

m = -2

Step-by-step explanation:

Let (x1 , y1 ) = ( 3 , 8) and (x2 , y2 ) = ( 2 , 10)

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hope it helps :)

4 0
3 years ago
Read 2 more answers
Help me with this problem please right away​
svlad2 [7]

Answer:

6\frac{1}{2} = A

Step-by-step explanation:

The first step is to use the Distance Formula to figure out the lengths of the two legs:

\sqrt{[-x_1 + x_2]^{2} + [-y_1 + y_2]^{2}} = D

R(1, 1) and P(−1, −2) ↷

\sqrt{[1 + 1]^{2} + [2 + 1]^{2}} = \sqrt{2^{2} + 3^{2}} = \sqrt{4 + 9} = \sqrt{13}\\ \\ \sqrt{13} = RP

Q(2, −4) and P(−1, −2) ↷

\sqrt{[1 + 2]^{2} + [2 - 4]^{2}} = \sqrt{[-2]^{2} + 3^{2}} = \sqrt{4 + 9} = \sqrt{13} \\ \\ \sqrt{13} = QP

* So, by my calculations, we have an isosceles <em>right triangle</em>, and according to the <em>45°-45°-90° triangle theorem</em>, we automatically know that the hypotenuse, <em>RQ</em>, is \sqrt{26}:

30°-60°-90° triangle theorem

2x, x, x√3

↑ ↑ ↑

h leg leg

y

p

o

t

e

n

u

s

e

45°-45°-90° triangle theorem

x√2, x, x

↑ ↑ ↑

h legs

y

p

o

t

e

n

u

s

e

So now, we have to find the area of the triangle by taking half of either height or base, then multiplying that by the height or base, but since this is an isosceles <em>right</em><em> </em><em>triangle</em><em>,</em><em> </em>it does not matter:

[\frac{h}{2}][b] = A \: \:OR\: \: [\frac{b}{2}][h] = A \: \:OR \: \: \frac{hb}{2} = A

[\frac{\sqrt{13}}{2}][\sqrt{13}] = \frac{13}{2} = 6\frac{1}{2} \\ \\ 6\frac{1}{2} = A

I am joyous to assist you anytime.

8 0
3 years ago
Simplify the following expression. *<br> 3(x-4)
damaskus [11]

Answer:

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Step-by-step explanation:

3(x-4)

Distribute

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6 0
4 years ago
-24 divided by x + 12 to the second when x= -14
ELEN [110]

Answer:12

Step-by-step explanation:

3 0
3 years ago
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