Given equations are;<span>
2a + 3b = -1 ..................equation 1
3a + 5b = -2 ....................equation 2</span>
Now multiply equation 1 with (-3)
The equation will be;
-6a -9b = 3 …………………..equation 3
Now multiply equation 2 with (2)
The equation will be;
6a + 10b = -4 ……………..equation 4
Now add equation 3 and equation 4
-6a – 9b = 3
<span>6a + 10b = -4</span>
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0a + b = -1
b = -1
Now put the value of b in equation 1
2a + 3(-1) = -1
2a -3 = -1
2a = -1+3
2a = 2
a=1
Thus the solution is (a,b) = (1,-1)
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Area=pi times radius^2
area=36pi
36pi=pi times radius^2
divide both sides by pi
36=radius^2
square root both sides
6=radius
2radius=diameter
2 times 6=12
radius=6
diamater=12
the answers area A and D
(if you know your radius and diameter, you would know that diameter is 2 times radius and you could eliminate 2 choices imedietly (B and C))
The length is 14
Just count the spaces in between to get the result of 14
