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shusha [124]
3 years ago
5

I don’t understand this

Mathematics
2 answers:
Alexandra [31]3 years ago
5 0

Answer:

-15.41

Step-by-step explanation:

big brain?

BartSMP [9]3 years ago
3 0

Answer:

-13.8

Step-by-step explanation:

6.7ₓ-2.3

Multiply 3 by 7

Multiply 3 by 6

Put a 0 in the ones place

Multiply 2 by 7

Multiply 2 by 6

Add the 2 answers

Add in the negative

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Maksim231197 [3]
You need to show what a and b are plz
5 0
3 years ago
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Given: ABCD ∥gram, BK ⊥ AD , AB ⊥ BD AB=6, AK=3 Find: m∠A, BK, Area of ABCD
Morgarella [4.7K]

1. Consider right triangle ABK. In this triangle AB is the hypotenuse, BK and AK are legs. By the Pythagorean theorem,

AB^2=AK^2+BK^2,\\\\6^2=3^2+BK^2,\\\\BK^2=36-9=27,\\\\BK=3\sqrt{3}\ un.

2. Use the definition of \cos \angle A:

\cos \angle A=\dfrac{\text{adjacent leg}}{\text{hypotenuse}}=\dfrac{AK}{AB}=\dfrac{3}{6}=\dfrac{1}{2}.

Then m\angle A=60^{\circ}.

3. Consider right triangle ABD. In this triangle AD is the hypotenuse, AB and BD are legs. Since  m\angle A=60^{\circ}, then

m\angle BDA=180^{\circ}-90^{\circ}-60^{\circ}=30^{\circ}.

The leg that is opposite to the angle of 30° is half of the hypotenuse, so

AD=2AB=12\ un.

4. The area of parallelogram aBCD is

A_{ABCD}=AD\cdot BK=12\cdot 3\sqrt{3}=36\sqrt{3}\ sq. un.

3 0
3 years ago
Y^3-9y^2+y-9 I don't know how to solve this can you help
aleksley [76]
I'm guessing your problem is this:
y³ - 9y² + y - 9 = 0
right?

In solving this problem, I recommend doing this:
y³ - 9y² + y - 9 = 0
Factor out a y² from the first two numbers in the problem:
y²(y - 9) + (y - 9) = 0
Separate the parentheses which means y - 9 goes on one side. The y² added a one since it came from the + 1 in the middle of expression. When you're separating parentheses like this you just take the outside numbers and combine them together. Since + 1 came from the outside of the (y - 9) and y² also was sitting on the outside of (y - 9) combine them to make y² + 1. Like this:
(y² + 1)(y - 9) = 0
Now separate your two parentheses to two separate problems:
(y² + 1) = 0    and    (y - 9) = 0
Now you're y² + 1 will equal:
y² = -1
y = √-1 <-- This number doesn't exist so it will be an imaginary number (i). If you guys didn't learn that in your class I recommend just leaving it as i for that part.
Now solve y - 9 = 0:
y = 9 <-- Since we added nine to both sides to get this.

So you're final answer should be y = i and 9
3 0
4 years ago
Find two positive numbers whose product is 36 and whose sum is a minimum.
alukav5142 [94]
Let one of the numbers be x. The other number cab then be represented as 36-x (x+36-x = 36).
The product can then be represented as y = x(36-x) or y=36x-x2

The maximum or minimum is always on the axis of symmetry which has the formula x=-b/2a.
In our case, the axis of symmetry is -36/-2, so x=18.

If one number is 18 and the 2 numbers add to 36, the other number is 18 as well.
So the 2 numbers are 18 and 18 and the maximum product is 324,
8 0
3 years ago
Isabel got her haircut for $16. she left a 15% tip. what is the total amount of money isabel paided?
Gnom [1K]
$16x.15=$2.40
16+2.4=18.40 the answer is $18.40
Hopefully this is helpful.
8 0
3 years ago
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