The time required for one wing beat is 5 milliseconds.
<em><u>Explanation</u></em>
Lets assume, the time required for one wing beat is 
seconds
So, the time required for 200 wing beat 
seconds
Given that, the honeybee flaps its wings 200 times per 1 second. So...
So, the time required for one wing beat is 5 milliseconds.
Answer:
125 meters squared
Step-by-step explanation:
Surface area of initial pyramid:
- A= 10²+4*1/2*10*15= 400 m²
Surface area of extended pyramid:
- A= 10*15+2*1/2*15*15+2*1/2*10*15= 525 m²
The difference is:
What are the directions for this?
Step-by-step explanation:
12(6) - 7(2) + (6-3)
48 - 14 + 2
36
Answer:
10
Step-by-step explanation:
So the unit rate in this situation is how many times Jazmine spun around in 1 minute, since unit is always 1. To find the answer you divide 20 by 2 which is equal to 10. She spun around 10 times in 1 minute, and 20 times in 2 minutes.
