if the -8-13 are both in the denominator
-24/(-8-13)
-24/-21
divide both sides by -3
[-24/-3] / [-21/-3]
8 / 7
if the -13 comes after the division
(-24/-8) -13
3 - 13
-10
Answer:
see explanation
Step-by-step explanation:
Using sum to product identities
cos x - cos y = - 2sin(
)sin(
) = 2sin(
)sin(
)
cos x + cos y = 2cos(
)cos(
)
Note that
sin10° = sin(90 - 10)° = cos80°
Thus
← cancel 2 from numerator/ denominator
=
× ![\frac{sin35}{cos35}](https://tex.z-dn.net/?f=%5Cfrac%7Bsin35%7D%7Bcos35%7D)
= tan45° × tan35° { tan45° = 1 ]
= 1 × tan35°
= tan35° ← as required
Here is the set up:
x
x + 2
x + 4
x^2 + (x + 2) + (x + 4)^2 = 170
Take it from here.
Both ways to write it our
- Zero Product Property: if a × b = 0, then either a or b = 0 or both a and b = 0.
(Make sure to set f(x) to zero)
So for this equation, I will be factoring by grouping. Firstly, what two terms have a product of -5x^2 and a sum of 4x? That would be 5x and -x. Replace 4x with 5x - x: ![0=5x^2+5x-x-1](https://tex.z-dn.net/?f=0%3D5x%5E2%2B5x-x-1)
Next, factor 5x^2 + 5x and -x - 1 separately. Make sure that they have the same quantity on the inside: ![0=5x(x+1)-1(x+1)](https://tex.z-dn.net/?f=0%3D5x%28x%2B1%29-1%28x%2B1%29)
Now you can rewrite the equation as: ![0=(5x-1)(x+1)](https://tex.z-dn.net/?f=0%3D%285x-1%29%28x%2B1%29)
Now apply zero product property to the factors to solve for x:
![5x-1=0\\5x=1\\x=\frac{1}{5}\\\\x+1=0\\x=-1](https://tex.z-dn.net/?f=5x-1%3D0%5C%5C5x%3D1%5C%5Cx%3D%5Cfrac%7B1%7D%7B5%7D%5C%5C%5C%5Cx%2B1%3D0%5C%5Cx%3D-1)
<u>The x-intercepts are (1/5 ,0) and (-1,0).</u>