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OLEGan [10]
2 years ago
15

The magnitude of an impulse produced by a 300 g mass rubber ball, striking a wall horizontally at a velocity of 40 m/s, that reb

ounds with the same velocity immediately upon striking.
24.0 N s
12.0 N s
12,000.0 N s
60.0 N s
SAT
1 answer:
8090 [49]2 years ago
7 0

Option a. The total force that is calculated is given as 24 n/s

<h3>How to solve for the magnitude</h3>

300 g = 0.3kg

Force = change in momentum / time

We have to find the mass x velocity

0.3 x 40 = 12kg m / s

This rubber ball is said to strike and also rebound immediately. We can take the time as 1 second.

Force 1 x 12

= 12 N

The force that is exerted after the rebounding has occurred is also 12 N following Newton's 3rd law.

The total force that is exerted would be calculated as 12N + 12N = 24 N/S

Read more on force here:

brainly.com/question/25239010

#SPJ1

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