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Marrrta [24]
3 years ago
5

What is the exact value of sin (- 105)?​

Mathematics
2 answers:
antoniya [11.8K]3 years ago
6 0

\text{Let's find the sine of -105 degrees}\\\text{Start by  typing -105 into our calculator}\\\text{and click the sin button}\\\text{It gives us an irrational number, which is the sine of -105 degrees}

\rule{300}{1.7}

\text{The value is end less, it would take an eternity to type it here,}\\\text{ but I will round it to the nearest 100th}

\rule{300}{1.7}

\text{-0.97}

Archy [21]3 years ago
3 0

Answer:

Just put it into a calculator

0.97053528353

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How do I solve this?
Hunter-Best [27]

9514 1404 393

Answer:

  • x = 10
  • y = 19

Step-by-step explanation:

Consecutive interior angles between parallel lines are supplementary.

Let's start with x.

  (8x +40)° +(6x)° = 180°

  14x +40 = 180 . . . . . . . . . divide by °, collect terms

  14x = 140 . . . . . . . . . subtract 40

  x = 10 . . . . . . . . divide by 14

__

We can use the same approach for y:

  (7y)° +(3y -10)° = 180°

  10y = 190 . . . . . . . . . . . divide by °, add 10, collect terms

  y = 19 . . . . . . . . . . . divide by 10

5 0
3 years ago
Use this figure to find the value of ∠FOD. <br><br> A. 27°<br> B. 63°<br> C. 46°<br> D. 78°
BartSMP [9]

m<FOD = 90 -12 -15

m<FOD = 63

answer is B. 63

hope it helps

7 0
4 years ago
Read 2 more answers
If the work required to stretch a spring 2 ft beyond its natural length is 9 ft-lb, how much work is needed to stretch it 18 in.
Blababa [14]

If the work required to stretch a spring 2 ft beyond its natural length is 9 ft-lb,then the work that is needed to stretch it 18 inches beyond its natural length is 81 ft.lb.

Given that work required to stretch a spring 2 ft beyond its natural length is 9 ft-lb.

We are required to find the work that is needed to stretch 18 inches beyond its natural length.

Multiplication is basically finding out the product of two or more numbers.

Work required to stretch the spring 2 feet beyond its natural length=9 ft. lb.

So, to find the work that is required to stretch the spring 18 feet beyond its natural length, we have to multiply 9 with 9 which will give us 81. So the work required is 81 ft.lb.

Hence if the work required to stretch a spring 2 ft beyond its natural length is 9 ft-lb,then the work that is needed to stretch it 18 inches beyond its natural length is 81 ft.-lb.

Learn more about multiplication at brainly.com/question/10873737

#SPJ4

5 0
1 year ago
Please help me with this.
Ierofanga [76]

Answer:

ok umm this looks hard can u give mor info?

Step-by-step explanation:

8 0
3 years ago
Please solve the right triangle below. Round the decimals to the nearest tenth.
aniked [119]

Find AB using Pythagorean Theorem,

AB=\sqrt{12^2+9^2}=15.

A=\tan^{-1}(12/9)=53.1^{\circ}.

B=\tan^{-1}(9/12)=36.9^{\circ}.

Hope this helps.

7 0
3 years ago
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