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pantera1 [17]
3 years ago
10

Leroy is a sales person. He sold a crystal vase for $203 and earned 13% commission. How much commission did Leroy earn?

Mathematics
2 answers:
NNADVOKAT [17]3 years ago
8 0

Answer:

For the vase, 26.39

Step-by-step explanation:

203*13%=26.39

Delicious77 [7]3 years ago
5 0
The answer is 26.39 to ur question
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Given the point (1, 3) and a slope of 2, write an equation in point-slope form.
Sunny_sXe [5.5K]

Answer:

y=2x+1

Step-by-step explanation:

Since we are given a point and a slope, we can use the point slope formula

y-y_{1} =m(x-x_{1})

m is the slope. In this case, m is 2.

y1 is the y coordinate of the point given. y1 is 3.

x1 is the x coordinate of the point given. x1 is 1

y-3=2(x-1)

Now, we need to get the equation into point slope form: y=mx+b

To do this, we need to get y by itself

First, distribute the 2 on the right

y-3=2*x+ 2*-1

y-3=2x-2

Add 3 to both sides

y-3+3=2x-2+3

y=2x+1

The equation is in y=mx+b form, so our final equation is:

y=2x+1

6 0
2 years ago
What is the midpoint
mrs_skeptik [129]
The answer is (4, 3). Hope this helps!
8 0
2 years ago
Product of 100 and sum of 25
ddd [48]

Answer:

100*25

Step-by-step explanation:

sum of 25=25

6 0
2 years ago
PLEASE HELP! I am doing Imagine Math and I need help with this question!
Vaselesa [24]
The bottom left option is when it is reflected over the x axis, the second to last option on the left is when it is reflected of the y axis, and the middle option is when it is reflected over the line y = x

Hope this helps :)
5 0
2 years ago
Find equations of the tangent plane and the normal line to the given surface at the specified point. x + y + z = 8exyz, (0, 0, 8
Dima020 [189]

Let f(x,y,z)=x+y+z-8e^{xyz}. The tangent plane to the surface at (0, 0, 8) is

\nabla f(0,0,8)\cdot(x,y,z-8)=0

The gradient is

\nabla f(x,y,z)=\left(1-8yze^{xyz},1-8xze^{xyz},1-8xye^{xyz}\right)

so the tangent plane's equation is

(1,1,1)\cdot(x,y,z-8)=0\implies x+y+(z-8)=0\implies x+y+z=8

The normal vector to the plane at (0, 0, 8) is the same as the gradient of the surface at this point, (1, 1, 1). We can get all points along the line containing this vector by scaling the vector by t, then ensure it passes through (0, 0, 8) by translating the line so that it does. Then the line has parametric equation

(1,1,1)t+(0,0,8)=(t,t,t+8)

or x(t)=t, y(t)=t, and z(t)=t+8.

(See the attached plot; the given surface is orange, (0, 0, 8) is the black point, the tangent plane is blue, and the red line is the normal at this point)

4 0
3 years ago
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