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vladimir2022 [97]

1 year ago

14

I am taking quiz corrections and as you see Iwrote one statement correct about theconstitution but I got the other 2 wrong.Based

on that construction what are 2 othercorrect statements?

1 answer:

gulaghasi [49]1 year ago

6 0

As we can see in the shown figure:

1) I and J are parallel

2) I and g are perpendicular because we have constructed the steps to make the perpendicular to the line I

3) J and g are perpendiculars because I and J are parallel and I perpendiculars to g

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Factorize : y^3 -2y^2 -29y -42

AVprozaik [17]

Answer: $(y-7)(y+3)(y+2)$

Step-by-step explanation:

$y^{3} -2y^{2}-29y-42\\\\(y^{2}-4y-21)(y+2)\\\\(y-7)(y+3)(y+2)\\\\$

Hope this helps, have a BLESSED AND WONDERFUL DAY! As well as a great Black History Month and Valentine's day! :-)

- Cutiepatutie ☺❀❤

7 0

3 years ago

You have checked model income statements and estimate your payroll expense will be 36% of revenue. You expect sales to be $9,000

aksik [14]

Answer:

Budget annual payroll = $168,480

Step-by-step explanation:

Given:

Expect sales per week = $9,000

Revenue over sales = 36% = 0.36

Find:

Budget annual payroll = ?

Computation:

Assume number of week per year = 52

⇒ Budget annual payroll = Expect sales per week × Number of week per year × Revenue over sales

⇒ Budget annual payroll = $9,000 × 52 × 0.36

⇒ Budget annual payroll = $168,480

3 0

3 years ago

Choose the slope-intercept form of y + 3 = 4(x - 5).

Scrat [10]

Answer: y=4x-23

Step-by-step explanation:

First multiply the 4 on the right side to make it y+3=4x-20. Then subtract 3 on both sides to get y=4x-23

5 0

3 years ago

Read 2 more answers

Find the product of all real values of r for which 1/2x=r-x/7

Dahasolnce [82]

Answer:

$r = \±\sqrt{14$

$Product = -14$

Step-by-step explanation:

Given

$\frac{1}{2x} = \frac{r - x}{7}$

Required

Find all product of real values that satisfy the equation

$\frac{1}{2x} = \frac{r - x}{7}$

Cross multiply:

$2x(r - x) = 7 * 1$

$2xr - 2x^2 = 7$

Subtract 7 from both sides

$2xr - 2x^2 -7= 7 -7$

$2xr - 2x^2 -7= 0$

Reorder

$- 2x^2+ 2xr -7= 0$

Multiply through by -1

$2x^2 - 2xr +7= 0$

The above represents a quadratic equation and as such could take either of the following conditions.

(1) No real roots:

This possibility does not apply in this case as such, would not be considered.

(2) One real root

This is true if

$b^2 - 4ac = 0$

For a quadratic equation

$ax^2 + bx + c = 0$

By comparison with $2x^2 - 2xr +7= 0$

$a = 2$

$b = -2r$

$c =7$

Substitute these values in $b^2 - 4ac = 0$

$(-2r)^2 - 4 * 2 * 7 = 0$

$4r^2 - 56 = 0$

Add 56 to both sides

$4r^2 - 56 + 56= 0 + 56$

$4r^2 = 56$

Divide through by 4

$r^2 = 14$

Take square roots

$\sqrt{r^2} = \±\sqrt{14$

$r = \±\sqrt{14$

Hence, the possible values of r are:

$\sqrt{14$ or $-\sqrt{14$

and the product is:

$Product = \sqrt{14} * -\sqrt{14}$

$Product = -14$

8 0

3 years ago

Which set represents the range of the function shown?<br> {(8, 2), (6, 5), (4, 7), (11, −2)}

kakasveta [241]

The second numbers in each of the ordered pairs is the range

3 0

3 years ago