If....................

Mathematics

2 answers:

Bad White [126]1 year ago

8 0

To solve for f(3)g(3):

* We know fg(x) means we need to multiply f with g replacing all x's with the x-value given

Replace all x's with 3

Solve for f(3)g(3)

$(3(3)^{2}-5)(-2(3)+5)\\(3(9)-5)(-6+5)\\22 * -1\\-22$

-22 is the answer

Hope it helps!

kobusy [5.1K]1 year ago

5 0

Answer:

C - 22

Step-by-step explanation:

Put in '3 ' for 'x' in both of the equations....then multiply the results together

f(3) = 3 (3)^2 - 5 = 22

g(3) = -1

22 * -1 = -22

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The drama club was selecting which carnival booths to sponsor at the fall carnival from a list of nine. How many different ways

denis-greek [22]

Answer:

Option B

Step-by-step explanation:

Here we have to apply " combination and permutation. " It is given that the drama club had to choose three booths from a selection of 9, considering the possible ways to choose so. This is a perfect example of combination. In nCr, n corresponds to 9, respectively r corresponds to 3.

$\mathrm{n\:choose\:r},\\nCr=\frac{n!}{r!\left(n-r\right)!},\\\\\frac{9!}{3!\left(9-3\right)!} =\\\frac{9!}{3!\cdot \:6!} =\\\\\frac{9\cdot \:8\cdot \:7}{3!} =\\\frac{504}{6} =\\\\84\\\\Solution = Option B$