Make more sense ou of this question and I can help you out more ok?
Answer:
Step-by-step explanation:
I used logic and took the easy way around this as opposed to the long, drawn-out algebraic way. I noticed right off that at x = -3 and x = -1 the y values were the same. In the middle of those two x-values is -2, which is the vertex of the parabola with coordinates (-2, 4). That's the h and k in the formula I'm going to use. Then I picked a point from the table to use as my x and y in the formula I'm going to use. I chose (0, 3) because it's easy. The formula for a quadratic is

and I have everything I need to solve for a. Filling in my h, k, x, and y:
and
and
-1 = 4a so

In work/vertex form the equation for the quadratic is

In standard form it's:

Answer:
A) 4
B) 13
C)17
D)34
Answer:
Step-by-step explanation:
A. 9p⁴q⁶
Because 3²=9, (p²)²=p⁴, and (q³)²=q⁶
–2a² + 4ab – 5a – 2b + b²
Solution:
Given data:
–2a(a + b – 5) + 3(–5a + 2b) + b(6a + b – 8)
<u>To solve this expression:</u>
Multiply each number or variable into the bracket.
–2a(a + b – 5) + 3(–5a + 2b) + b(6a + b – 8)
= –2a² – 2ab + 10a – 15a + 6b + 6ab + b² – 8b
Arrange like terms together.
= –2a² – 2ab + 6ab + 10a – 15a + 6b – 8b + b²
= –2a² + 4ab – 5a – 2b + b²
Hence the solution is –2a² + 4ab – 5a – 2b + b².