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jeka94
2 years ago
13

If P = (3,2), find the image

Mathematics
1 answer:
Tamiku [17]2 years ago
4 0

Given:

The point P = (3,2) is rotated 270° counterclockwise about the origin.

To find:

The image of the given point after rotation.

Solution:

If a point rotated 270° counterclockwise about the origin, then the rule of rotation is:

(x,y)\to (y,-x)

Using this rule, we get

P(3,2)\to P'(2,-3)

Therefore, the image of given point P = (3,2) after the rotation of 270° counterclockwise about the origin, is P'(2,-3).

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What is the equation of the quadratic function represented by this table?
MA_775_DIABLO [31]

Answer:

Step-by-step explanation:

I used logic and took the easy way around this as opposed to the long, drawn-out algebraic way.  I noticed right off that at x = -3 and x = -1 the y values were the same.  In the middle of those two x-values is -2, which is the vertex of the parabola with coordinates (-2, 4).  That's the h and k in the formula I'm going to use.  Then I picked a point from the table to use as my x and y in the formula I'm going to use.  I chose (0, 3) because it's easy.  The formula for a quadratic is

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8 0
3 years ago
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1 year ago
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Elan Coil [88]

Answer:

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6 0
3 years ago
ALGEBRA NATION Question 5 of 10 < Previous Question Next Question > Rewrite the expression below. -2a(a + b – 5) + 3(-5a +
Ierofanga [76]

–2a² + 4ab – 5a – 2b + b²

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Given data:

–2a(a + b – 5) + 3(–5a + 2b) + b(6a + b – 8)

<u>To solve this expression:</u>

Multiply each number or variable into the bracket.

–2a(a + b – 5) + 3(–5a + 2b) + b(6a + b – 8)

        = –2a² – 2ab + 10a – 15a + 6b + 6ab + b² – 8b

Arrange like terms together.      

       = –2a² – 2ab + 6ab + 10a – 15a + 6b – 8b + b²

       = –2a² + 4ab – 5a – 2b + b²

Hence the solution is  –2a² + 4ab – 5a – 2b + b².

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2 years ago
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