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Evgen [1.6K]
2 years ago
10

PLEASE HELP!

Mathematics
2 answers:
aivan3 [116]2 years ago
8 0

Answer:

135

Step-by-step explanation:

Juliette [100K]2 years ago
6 0

Answer: 135 miles

Step-by-step explanation: If you go 70 miles in ones hour, then you’ll go 140 miles in 2 hours. Then it took 6 minutes longer because of traffic, and in traffic he drove 1 mile excluding 5 because he was 5 mph slower.

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Natalie visits a grocery store to buy tomatoes.The cost of tomatoes is $26.She remitted the bill and received $4 in change from
yKpoI14uk [10]
$30
You need to add $4 to $26 since the tomatoes were 26 dollars and she received 4 back
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2 years ago
I need help on this problem. Does anyone know how to complete it? Please and thank you :)
ale4655 [162]
I think it's 5 because i remember learning that it's gonna be half of what the bottom is
4 0
2 years ago
7 + (10 − 4)2 ÷ 4 × 1\8
natta225 [31]
I’m pretty sure the answer is 12

6 0
2 years ago
Show all four symbols of multiplication using the variables a/b
OlgaM077 [116]

Answer:

Multiplication Symbols:

<u>1.</u><u> Times</u> ×

<u>2.</u><u> Dot</u>  ⋅

<u>3.</u><u> Parentheses</u> ()

<u>4.</u><u> Variables next to each other</u> <em>ab</em>

Step-by-step explanation:

The symbols can be used like this...

Times: <em>a</em> × <em>b</em> = <em>c</em>

Dot: <em>a</em> ⋅ <em>b</em> = <em>c</em>

Parentheses:<em> </em>(<em>a</em>)(<em>b</em>) = <em>c</em>

Variables next to each other: <em>ab </em>= <em>c</em>

5 0
2 years ago
If α and β are the zeros of the quadratic polynomial f(x) = 3x2–4x + 5, find a polynomialwhose zeros are 2α + 3β and 3α + 2β.
Lelechka [254]

Answer:

\boxed{\sf \ \ \ 3x^2-20x+37\ \ \ }

Step-by-step explanation:

Hello,

a and b are the zeros, we can say that

f(x)=3(x^2-\dfrac{4}{3}x+\dfrac{5}{3}) = 3(x-a)(x-b)=3(x-(a+b)x+ab)

So we can say that

a+b=\dfrac{4}{3}\\ab=\dfrac{5}{3}

Now, we are looking for a polynomial where zeros are 2a+3b and 3a+2b

for instance we can write

(x-2a-3b)(x-3a-2b)=x^2-(2a+3b+3a+2b)x+(2a+3b)(3a+2b)\\= x^2-5(a+b)x+6a^2+6b^2+9ab+4ab

and we can notice that

a^2+b^2=(a+b)^2-2ab so

(x-2a-3b)(x-3a-2b)=x^2-5(a+b)x+6[(a+b)2-2ab]+13ab\\= x^2-5(a+b)x+6(a+b)^2+ab

it comes

x^2-5*\dfrac{4}{3}x+6(\dfrac{4}{3})^2+\dfrac{5}{3}

multiply by 3

3x^2-20x+2*16+5=3x^2-20x+37

4 0
3 years ago
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