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lara31 [8.8K]
1 year ago
11

Can't seem to solve this one

Mathematics
1 answer:
NeTakaya1 year ago
7 0

Answer:

.88

Step-by-step explanation:

\sqrt{.7775}  = .88

The standard deviation is the square root of the variance.

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A ballroom in a hotel has the shape shown in the diagram. The hotel manager needs to determine how much carpet is needed to reca
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Determine whether the relation is a function. {(−3,−6),(−2,−4),(−1,−2),(0,0),(1,2),(2,4),(3,6)}
Gennadij [26K]

Answer:

The relation is a function.

Step-by-step explanation:

In order for the relation to be a function, every input must only have one output. Basically, you can't have 2 outputs for 1 input but you can have 2 inputs for 1 output. Looking at all of the points in the relation, we see that no input has multiple outputs, so the answer is yes, the relation is a function.

7 0
3 years ago
Erik correctly rounds three numbers. One and StartFraction 7 over 29 EndFraction rounds to 1 One and five-sixths rounds to 2 0.1
Leya [2.2K]

Answer:

From greatest to least

One and five-sixth rounded to 2

One and StartFraction 7 over 29 rounded to 1

0.16 rounded to 0

Step-by-step explanation:

1+7/29=29+7/29

=36/29

=1.24

Approximately

=1

1+5/6=6+5/6

=11/6

=1.83

Approximately

=2

0.16

Approximately =0

From greatest to least

One and five-sixth rounded to 2

One and StartFraction 7 over 29 rounded to 1

0.16 rounded to 0

7 0
3 years ago
Gravel is being dumped from a conveyor belt at a rate of 20 ft3 /min and its coarseness is such that it forms a pile in the shap
pantera1 [17]

Answer:

The height of the pile is increasing at the rate of  \mathbf{ \dfrac{20}{56.25 \pi}   \ \ \ \ \  ft/min}

Step-by-step explanation:

Given that :

Gravel is being dumped from a conveyor belt at a rate of 20 ft³ /min

i.e \dfrac{dV}{dt}= 20 \ ft^3/min

we know that radius r is always twice the   diameter d

i.e d = 2r

Given that :

the shape of a cone whose base diameter and height are always equal.

then d = h = 2r

h = 2r

r = h/2

The volume of a cone can be given by the formula:

V = \dfrac{\pi r^2 h}{3}

V = \dfrac{\pi (h/2)^2 h}{3}

V = \dfrac{1}{12} \pi h^3

V = \dfrac{ \pi h^3}{12}

Taking the differentiation of volume V with respect to time t; we have:

\dfrac{dV}{dt }= (\dfrac{d}{dh}(\dfrac{\pi h^3}{12})) \times \dfrac{dh}{dt}

\dfrac{dV}{dt }= (\dfrac{\pi h^2}{4} ) \times \dfrac{dh}{dt}

we know that:

\dfrac{dV}{dt}= 20 \ ft^3/min

So;we have:

20= (\dfrac{\pi (15)^2}{4} ) \times \dfrac{dh}{dt}

20= 56.25 \pi \times \dfrac{dh}{dt}

\mathbf{\dfrac{dh}{dt}= \dfrac{20}{56.25 \pi}   \ \ \ \ \  ft/min}

The height of the pile is increasing at the rate of  \mathbf{ \dfrac{20}{56.25 \pi}   \ \ \ \ \  ft/min}

8 0
3 years ago
Gloria earned $26 for babysitting for 4 hours. Write and Solve an equation to determine how much Gloria would earn after babysit
posledela

Answer:

Equation: ($26÷4 hours) × 25 hours

Answer: $156.25

Step-by-step explanation:

First, you would have to find out how much she earns per hour, so $26÷4. Then you multiply that by 25.

(26÷4) x 25=$156.25.

(hope this helps :P)

3 0
3 years ago
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