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vlabodo [156]
3 years ago
9

The product of the slopes of perpendicular lines is always

Mathematics
1 answer:
kicyunya [14]3 years ago
5 0
<span>The product of the slopes of perpendicular lines is always equal to -1

Hope this helps!</span>
You might be interested in
Order the following from greatest to least: -12,12,-19,1 and 1/2,5.....
den301095 [7]
-19, -12, 1/2, 1, 5, 12 ----> least to greatest
12, 5, 1, 1/2, -12, -19 ----> greatest to least

Do the same as the last one, starting with the largest negative number, and ending with the largest positive number.  The only difference in this case is that it is greatest to least.  I tend to go from least to greatest first and then flip it around to get greatest to least (:
3 0
3 years ago
Help me Please....................
MakcuM [25]

9514 1404 393

Answer:

  1.3363

Step-by-step explanation:

The basic idea here is to find an expression for the direction vector between a point on L1 and a point on L2. Then, solve for the points on L1 and L2 that make that vector perpendicular to both lines L1 and L2. (The dot product of direction vectors is zero.) The distance between the points found is the shortest distance between the lines.

__

Let P be a point on L1. Then the parametric equation for P is ...

  P = (6t, 0, -t) . . . . . . origin + t × direction vector

Let Q be a point on L2. The direction vector for L2 is given by the difference between the given points. It is (4-1, 1-(-1), 6-1) = (3, 2, 5). Then the parametric equation for Q is ...

  Q = (3s+1, 2s-1, 5s+1) . . . . (1, -1, 1) + s × direction vector

The direction vector for PQ is ...

  Q -P = (3s+1-6t, 2s-1, 5s+1+t)

The dot product of this and the two lines' direction vectors will be zero:

  (3s+1-6t, 2s-1, 5s+1+t)·(6, 0, -1) = 0 = 13s -37t +5 . . . perpendicular to L1

  (3s+1-6t, 2s-1, 5s+1+t)·(3, 2, 5) = 0 = 38s -13t +6 . . . perpendicular to L2

The solution to these equations is ...

  s = -157/1237

  t = 112/1237

Then (Q-P) becomes (94, -1551, 564)/1237, and its length is ...

  |PQ| = √(94² +1551² +564²)/1237 ≈ 1.3363

The distance between the two lines is about 1.3363 units.

8 0
3 years ago
Hellllllllllllllllpppppppppppppp
Roman55 [17]
I’m pretty sure it’s a
4 0
3 years ago
Read 2 more answers
Solve, using linear combination. 5x + y = 2 4x + y = 4
mylen [45]
I hope this helps you

3 0
3 years ago
On a hiking trip LaShana notes that she hiked about 12 kilometers every 4 hours. If she continues at this rate' how many kilomet
scoray [572]

Answer:

18 Kilometers

Step-by-step explanation:

If you divide 12 by 4 you get 3, so she is going about 3 kilometers an hour. Add 3 for each hour, and you get 18 kilometers in 6 hours.

8 0
3 years ago
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