times more stars are there in universe compared to human eye can see
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Solution:</u></h3>
Given that, conservative estimate of the number of stars in the universe is 
The average human can see about 3,000 stars at night with only their eyes
To find: Number of times more stars are there in the universe, compared to the stars a human can see
Let "x" be the number of times more stars are there in the universe, compared to the stars a human can see
Then from given statement,
<em><u>Substituting given values we get,</u></em>
Thus times more stars are there in universe compared to human eye can see
100 = x + x/2
3x/2 = 100
x = 200/3
if there was 50% discount:
buying 1 would be $33.33
buying 2 would be $66.67
Answer:
What do you mean, I'll help.
Step-by-step explanation:
Answer:
59 to 66
Step-by-step explanation:
Mean test scores = u = 74.2
Standard Deviation = 
= 9.6
According to the given data, following is the range of grades:
Grade A: 85% to 100%
Grade B: 55% to 85%
Grade C: 19% to 55%
Grade D: 6% to 19%
Grade F: 0% to 6%
So, the grade D will be given to the students from 6% to 19% scores. We can convert these percentages to numerical limits using the z scores. First we need to to identify the corresponding z scores of these limits.
6% to 19% in decimal form would be 0.06 to 0.19. Corresponding z score for 0.06 is -1.56 and that for 0.19 is -0.88 (From the z table)
The formula for z score is:
For z = -1.56, we get:
For z = -0.88, we get:
Therefore, a numerical limits for a D grade would be from 59 to 66 (rounded to nearest whole numbers)
Answer:
(x) = 1/2x-3/2
Step-by-step explanation:
The inverse is the opposite of the equation given in this case is 2x+3 and the inverse is when you switch the x and the y and you solve for y.
