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Bezzdna [24]
2 years ago
15

The values in the table represent a linear function. How does the value of y change in relation to a change in the value of x?

Mathematics
1 answer:
Verizon [17]2 years ago
7 0

if x is changed by 2 , the y changes by  +3, Option B is the correct answer.

<h3>What is the  equation of a Linear Function ?</h3>

The equation of a Linear Function is given by

y = mx +c

here m is the slope , c is the intercept on the y axis

The data is given in the table

To determine the relation , a function needs to be established between the variables.

m = ( y2 -y1 )/(x2-x1)

m = (-7 +10) /(-2+4)

m = 3 / 2

y = (3/2)x + c

at x = 0 , y= -4

-4 = 0 + c

c = -4

The function is

y = (3/2) x - 4

if x is changed by 2 , the y changes by  +3

Therefore Option B is the correct answer.

To know more about Linear Function

brainly.com/question/21107621

#SPJ1

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Answer:

x- 3y - 7=0

Step-by-step explanation:

the line in the slope-intercept form:

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m= 1/3 and point given (1, -2) by using which we find y-intercept:

  • b= y-1/3x
  • b= -2- 1/3*1= - 7/3
  • y= 1/3x- 7/3

General form of a line is: ax+by+c= 0

converting:

  • y= 1/3x- 7/3  ⇒  3y= x- 7  ⇒  x- 3y - 7=0
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Evaluate the expression
larisa86 [58]

Answer:

12-[20-2(6^2\div3\times2^2)]=88

Step-by-step explanation:

So we have the expression:

12-[20-2(6^2\div3\times2^2)]

Recall the order of operations or PEMDAS:

P: Operations within parentheses must be done first. On a side note, do parentheses before brackets.

E: Within the parentheses, if exponents are present, do them before all other operations.

M/D: Multiplication and division next, whichever comes first.

A/S: Addition and subtraction next, whichever comes first.

(Note: This is how the order of operations is traditionally taught and how it was to me. If this is different for you, I do apologize. However, the answer should be the same.)

Thus, we should do the operations inside the parentheses first. Therefore:

12-[20-2(6^2\div3\times2^2)]

The parentheses is:

(6^2\div3\times2^2)

Square the 6 and the 4:

(36\div3\times4)

Do the operations from left to right. 36 divided by 3 is 12. 12 times 4 is 48:

(36\div3\times4)\\=(12\times4)\\=48

Therefore, the original equation is now:

12-[20-2(6^2\div3\times2^2)]\\=12- [20-2(48)]

Multiply with the brackets:

=12-[20-96]

Subtract with the brackets:

=12-[-76]

Two negatives make a positive. Add:

=12+76=88

Therefore:

12-[20-2(6^2\div3\times2^2)]=88

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3 years ago
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