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Triss [41]
3 years ago
14

A box has dimensions of 11 inches long, 4.4 feet wide, and 6 inches high. What is the volume of the box? The formula for the vol

ume is V = l · w · h. 290.4 in3 871.2 in3 2,904 in3 3,484.8 in3
Mathematics
2 answers:
Advocard [28]3 years ago
8 0

Answer:

Option 4 - 3484.8 inch cube.

Step-by-step explanation:

Given :  A box has dimensions of 11 inches long, 4.4 feet wide, and 6 inches high.

To find : What is the volume of the box?

Solution :

Dimension of box,

Length = 11 inches

Height = 6 inches

Breadth = 4.4 feet

We know, 1 foot = 12 inches

So, Breadth = 12\times 4.4=52.8

The formula for the volume of box is

V=l\times b\times h

V=11\times 52.8\times 6

V=3484.8 in^3

Therefore, option 4 is correct.

The volume of the box is 3484.8 inch cube.

xxMikexx [17]3 years ago
3 0

Answer:

3484.8 in inches

Step-by-step explanation:

turn feet to inches and multiply all values


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Indicate the equation of the given line in standard form.The line containing the median of the trapezoid whose vertices are R(-1
maxonik [38]
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y - 8 = -10/6 (x - 1) = -5/3 (x - 1) => slope = -5/3
TU => y - (-2) = (0 - (-2))/(2 - 7) (x - 7)
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y = -5/3 (x - 2) => slope = -5/3

The median is the line joining the midpoints of the non-parallel sides.
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Midpoint of TU = ((7 + 2)/2, -2/2) = (9/2, -1)

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P=3

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

−2=5p+3p−8−6p

−2=5p+3p+−8+−6p

−2=(5p+3p+−6p)+(−8)(Combine Like Terms)

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Step 3: Add 8 to both sides.

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Step 4: Divide both sides by 2.

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3 years ago
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