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dezoksy [38]
3 years ago
7

What is the product of 14560 times 10

Mathematics
1 answer:
Andrews [41]3 years ago
3 0
The product of 14560 and 10 is 145600
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Find the product and sum of the roots of the equation:<br> 2x^2-9x-10=0
BabaBlast [244]

Answer:

<h3>           sum of the roots:    x_1+x_2=4\frac12</h3><h3>           product of the roots:     x_1x_2=-5             </h3><h3> Step-by-step explanation:</h3>

2x^2-9x-10=0\quad\implies\quad a=2\,,\ b=-9\,,\ c=-10

b^2-4ac=(-9)^2-4(2)(-10)=81+80=161>0

From Vieta's formulas applied to quadratic polynomial we have:

if    b^2-4ac\geqslant0   then

sum of roots:    x_1+x_2=-\dfrac ba=-\dfrac{-9}2=4\frac12

product of the roots:     x_1x_2=\dfrac ca=\dfrac{-10}2=-5

3 0
3 years ago
The volume of a cylinder is 4x3 cubic units and its height is x units.
Anastasy [175]

Answer:

The answer to your question is r = 2x

Step-by-step explanation:

Volume of a cylinder = V = π r² h

r = radius

h = height = x

Volume = 4x³

Then

                  r² = \frac{volume}{\pi h}

                  r² = \frac{4x^{3} }{\pi x}

                  r² = 4x²

                  r = 2x

7 0
2 years ago
1.5 divided by 2.5 round to the nearest tenth
olga2289 [7]
The answer 0.6 i apologize if it is incorrect!
3 0
3 years ago
Please help this is timed test ❤️
drek231 [11]

Answer:

A.

Step-by-step explanation:

6 0
2 years ago
Every day, a comes to the bus stop at the same time, and boards the first bus that arrives. the arrival of the first bus is an e
mylen [45]
So the waiting time for a bus has density f(t)=λe−λtf(t)=λe−λt, where λλ is the rate. To understand the rate, you know that f(t)dtf(t)dt is a probability, so λλ has units of 1/[t]1/[t]. Thus if your bus arrives rr times per hour, the rate would be λ=rλ=r. Since the expectation of an exponential distribution is 1/λ1/λ, the higher your rate, the quicker you'll see a bus, which makes sense.

So define <span><span>X=min(<span>B1</span>,<span>B2</span>)</span><span>X=min(<span>B1</span>,<span>B2</span>)</span></span>, where <span><span>B1</span><span>B1</span></span> is exponential with rate <span>33</span> and <span><span>B2</span><span>B2</span></span> has rate <span>44</span>. It's easy to show the minimum of two independent exponentials is another exponential with rate <span><span><span>λ1</span>+<span>λ2</span></span><span><span>λ1</span>+<span>λ2</span></span></span>. So you want:

<span><span>P(X>20 minutes)=P(X>1/3)=1−F(1/3),</span><span>P(X>20 minutes)=P(X>1/3)=1−F(1/3),</span></span>

where <span><span>F(t)=1−<span>e<span>−t(<span>λ1</span>+<span>λ2</span>)</span></span></span><span>F(t)=1−<span>e<span>−t(<span>λ1</span>+<span>λ2</span>)</span></span></span></span>.

8 0
2 years ago
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