The work done by the gas when the gas expands will be 567.65 ft-lb.
<h3>What is the work done for an isothermal process?</h3>
The Pressure is inversely proportional to the volume.
Let the initial pressure and initial volume be P₁ and V₁, and the final volume be V₂.
Then the work done by the gas will be
WD = P₁ V₁ ln (V₂ / V₁)
A quantity of the gas with an initial volume of 2 cubic feet and an initial pressure of 700 pounds per square foot.
The gas expands to a volume of 3 cubic feet.
Then the work done by the gas will be
WD = 700 x 2 x ln (3/2)
WD = 1400 x 0.405
WD = 567.65 ft-lb
The work done by the gas when the gas expands will be 567.65 ft-lb.
More about the work done for isothermal process link is given below.
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Answer:
x + 4y = 4
4y = 4 - x
multiply both sides by 1/4
y = 1/4( 4- x)
y = 1- 1/4x
I think 710 is the answer
266+266+89+89= 710
Answer: Is there some answer choices? Because I can't help if I don't have any choices.
Step-by-step explanation:
