Answer:
It can be concluded that the intersection of a chord and the radius that bisects it is at right angle. The two are perpendicular.
Step-by-step explanation:
i. Construct the required circle of any radius as given in the question, then locate the chord. A chord joins two points on the circumference of a circle, but not passing through its center.
ii. Construct the radius to bisect the chord, dividing it into two equal parts.
Then it would be observed that the intersection of a chord and the radius that bisects it is at right angle. Thus, the chord and radius are are perpendicular to each other.
The construction to the question is herewith attached to this answer for more clarifications.
Answer:
34%
Step-by-step explanation:
the graph is a hundred so all you have to do is count the number of squares which is 34
If one-sixth of a certain number is four more than one-twelfth the number, the required number will be 48.
Let the unknown number be 'a'
One-sixth of the number is expressed as 1/6 a ..... 1
One-twelfth the number is also expressed as 1/12 a
Four more than one-twelfth the number will be written as:
1/12 a + 4 .... 2
Equating 1 and 2 will give:
1/6 a = 1/12 a + 4
a/6 = a/12 + 4
Collect the like terms
Find the LCM
Cross multiply
a = 12×4
a = 48
This shows that the required number is 48
Learn more on equations here: brainly.com/question/14034270